Top Answer

Of course the primes cannot be unique since 2x3x5x7=210>84.

The answer is 2x2x3x7.

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0No prime numbers equal 84. The only number equal to 84 is 84,and it isn't a prime number.The prime factors of 84 are: 1, 2, 2, 3, and 7

Prime factors of 84 are 2 x 2 x 3 x 7. There are not four different prime numbers that produce a product of 84.

The prime factors of 84 are 2x2x3x7.

As a product of its prime factors: 2*2*3*7 = 84

They are: 2^2 times 3 times 7 = 84

The numbers are -12 and 84

because when you multiply 2x2 it =4 then you multiply 4x3=12 then you multiply 12x7=wich you will have your answer 84!

9.165151389911680013176094387456 Solution: n * n = 84 n ^2 = 84 n = sqrt (84) n = 9.165151389911680013176094387456 check: 9.165151389911680013176094387456^2 = 84 = true! If you don't mean the square root of 84, then there are a number of numbers you can multiply to get 84, such as these: 42 * 2 28 * 3 21 * 4 14 * 6 7 * 12

No. In order for two factors (i.e. two numbers multiplied together) to result in an even number, at least one of the factors must be even. Except for "2" all prime numbers by definition must be odd numbers. 168/2 = 84. 84 is not prime. Therefore you are looking for 2 odd factors of 168. But this is a fruitless search as 2 odd numbers multiplied together will never result in an even number.

56 and 84 are both composite numbers, so neither are prime and they are not relatively prime either as they share several factors.

x/1 + x/x = 84 where x = a prime number that is divisible by 1 and itself. Then find common denominator of 1x. Then we have x squared/1x + x/1x = 84. To simplify this will be x squared + x/1x = 84. The this becomes 1 + x = 84. Then x = 83. The prime numbers are 1 and 83 which fit the equation.

If you mean prime factors then: 2, 2, 7, 3. Multiply those numbers by each other in various combinations to find all the factors of 84.

They can be: 4*3*7 = 84

The prime factors of 84 are 2, 2, 3, and 7.

To do this, you first have to break 84 and 108 down into their prime factors: 84 = 2x2x3x7 108 = 2x2x3x3x3 The next step is to identify any common prime factors. In this case both numbers have two 2s and a 3 as prime factors. Multiply these together and you get 12. Therefore the HCF of 84 and 108 is 12.

84 and 91 are composite numbers 67 and 73 are prime numbers

You'll need four. 2 x 3 x 3 x 7 = 84

you could multiply 84 by 10 = 840 then multiply 84 by 2 = 168 add these two numbers = 1008

As a product of its prime factors: 2*2*3*7 = 84

there is none it is a composite it is 1 and 84(it self )

Is 84 even? Yes, 84 = 2*42 Is 42 even? Yes, 42 = 2*21 Is 21 even? No -- no more factors of 2. Is 21 a multiple of 3? Yes, 21 = 3*7 7 is prime number. So 84 has been factored into primes. 84 = 2*2*3*7 That's the answer.

The prime factorization of 84 is 22 x 3 x 7.

The prime factorization of 84 is 2 x 2 x 3 x 7.

If two prime number have a sum of 54 they cannot have a sum of 84, and conversely.

84 is not a prime. All numbers ending in four are composite.

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