These are all independent events. So the probability of them all happening is the product of the probabilities of each one of them happening. The desired probability is (2/6)*(1/2)*(1/2)=1/12
It is 1/12.
With one toss of a coin, there can be at most 1 head. So the probability of 4 or more heads is very definitely 0.
The probability of rolling a number greater than 1 is 5/6.
The answer will depend on what is being tossed!
If the coin is tossed and the die rolled sufficiently many times then the probability is 1: the event is a certainty.For just one toss and roll, the probability is 0.25
The answer depends on the experiment: how many coins are tossed, how often, how many dice are rolled, how often.
Coins do not have numbers, there is only the probability of heads or tails.
These are independent one has no bearing on the other
The probability that the die tossed will land on a number that is smaller than 5 is 4/6 or 2/3. Smaller than 5 is 1 - 4 and 6 is the sample space.
The probability is 90/216 = 5/12
well, it will have 6 times of the greater chance.
The probability is 1/16.
A single fair die has the numbers 1 to 6, so when a single fair die is tossed the probability of obtaining a number different than 11 is: P(x diff than11) = 1.
1 - (2/3)4 = 1 - 16/81 = 65/81 ≈ 80.25%
There is only one even number over 4, which is 6, so when rolling the number cube, the chances of it coming up are 1/6.
1/4 if they are tossed only once.
The probability is 0.5The probability is 0.5The probability is 0.5The probability is 0.5
The probability is 50-50.
The number of times a coin is tossed does not alter the probability of getting heads, which is 50% in every case, as long as the coin has not been rigged (i.e., a double-headed coin, a weighted coin) to alter the result.