look at 1+3=4=2^2

1+3+5=9=3^2

1+3+5+7=16=4^2

The sum of the first n odd numbers is n^2!

Now how many are there?

look at 1-9 inclusive.. 1,3,5,7,9 there are 5

1-19-...there are 10 which is 20/2

so 1-99 should be 50 of them and the answer should be 50^2=2500

Think the young Euler's way:

-How many integer numbers are there from 1 to 100 inclusive? 100.

-How many of them are the odds and how many are the evens? 50 and 50.

So, from 1 to 100 inclusive there are 50 odds: 1, 3, 5, 7, 9, 11, ..., ..., ... , 95, 97 and 99.

Take them added together:

1 + 3 + 5 + 7 + 9 +11+13+...+93+95+97+99 (50 odds in total)

99+97+95+93+91+89+87+...+ 7+ 5 + 3 + 1 (50 odds in total)

Add the vertical pairs and their sums together:

(1+99)+(3+97)+(5+95)+(7+93)+(9+91)+...+(97+3)+(99+1).

-You can see that every pair added in each brachet gives 100 as a sum.

-How many pairs in brachets were added? 50 pairs.

So, since each pair gives 100 as a sum and there are 50 pairs in total, we take a total sum of 50x100=5000. But we took TWICE all the (50) odd numbers from 1 to 99 inclusive in order to add them in equal-summing pairs. So, we took TWICE their sum found out to be 5000. Then, their (single) sum must be 5000:2=2500.

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There are 21 prime numbers between 100 and 199 inclusive. These are as follows: 101 103 107 109 113 127 131 137 139 149 151 157 163 167 173 179 181 191 193 197 199

199 is a prime number; it has no composite factors.

It is: 199+99 = 298

200

If ever you have an odd number of negative numbers, the product will always be a negative number. So the answer to this question is negative.

You add both together and then divide by how many values you added. in this case 50 + 149 = 199 there are two values so divide by 2 199/2 = 99.5 So average is 99.5

199 31+37+41+43+47=199

The least of the three numbers is 199.

199, 200, 201

100

50

No. 17/27 is not the same as 125/199 or equivalently, 17/125 is not the same as 27/199

1 2 199 and 398.

198, 199 and 200 if you add them.

-99

The answer is 242. Simply add the numbers together arithmetically as you would for the problem two plus two. To check your work, a calculator is the best option.

2 + 3 + 199 = 204

191, 193, 197, 199.

603

There are 12 numbers between 100 and 199 that are divisible by eight: 104, 112, 120, 128, 136, 144, 152, 160, 168, 176, 184 and 192.

101 to 199 give 50 odd numbers. Their sum is 7,500.[I'm not too certain that the question meant 'the average total'? But, the odd numbers average total would be 7,500 ÷ 50 = 150]

They are: 191, 193, 197 and 199

The primes between 150 and 200 are: 151,157,163,167,173,179,181,191,193,197, and 199

101 103 107 109 113 127 131 137 139 149 151 157 163 167 173 179 181 191 193 197 199.

101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199