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What are the effects of acceleration due to gravity on the time period of a pendulum?
Wiki User
∙ 11y ago
The period of a pendulum (in seconds) is 2(pi)√(L/g), where L is the length and g is the acceleration due to gravity.
As acceleration due to gravity increases, the period decreases, so the smaller the acceleration due to gravity, the longer the period of the pendulum.
Wiki User
∙ 11y ago
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Why does accerlation due to gravity affect the period of a pendulum?
The period of a pendulum is give approximately by the formula t = 2*pi*sqrt(l/g) where l is the length of the pendulum and g is the acceleration (not accerlation) due to gravity. Thus g is part of the formula for the period.
How do you find time period of pendulum?
T=2π√(L/g)where L is the length of the pendulum and g is the local acceleration of gravity.
What is the difference in period for a pendulum on earth and a pendulum on moon?
The period of a simple pendulum swinging at a small angle is approximately 2*pi*Sqrt(L/g), where L is the length of the pendulum, and g is acceleration due to gravity. Since gravity on the moon is approximately 1/6 of Earth's gravity, the period of a pendulum on the moon with the same length will be approximately 2.45 times of the same pendulum on the Earth (that's square root of 6).
Is the period of the pendulum influenced by the point from which it is released?
No Time period, T = 2π √(l/g) π - pi l - lenght of the pendulum g - acceleration due to gravity at the place
How does the bob affects the period of a pendulum?
The period of a pendulum is totally un-affected by the mass of the bob.The time period of pendulum is given by the eqn.T=2*PIE*(l/g)1/2 ;l is the length of pendulum;g is the acceleration due to gravity.'l' is the length from the centre of suspension to the centre of gravity the bob.ie.the length of the pendulum depends on the centre of gravity of the bob,and hence the distribution of mass of the bob.
Does the weight effect the period of a pendulum?
It doesn't. Period depends on the length of the pendulum and the acceleration of gravity. Adding weight doesn't change the period at all.
What are the factors on which the time period of simple pendulum depends?
The length of the pendulum, and the acceleration due to gravity. Despite what many people believe, the mass has nothing to do with the period of a pendulum.
What are two factors that alter the oscillation period of a pendulum?
1. Length of the pendulum 2. acceleration due to gravity at that place
If a simple pendulum with a period of 1 second is set in motion of the moon what is the new period of this pendulum?
The equation is: http://hyperphysics.phy-astr.gsu.edu/HBASE/imgmec/pend.gif T is the period in seconds, L is pendulum length in cm, g is acceleration of gravity in m/s2. We know on earth the period is 1s when the acceleration of gravity is 9.8m/s2, so the pendulum length is 24.824cm. The acceleration of gravity on the moon is 1.6m/s2. Substitute 24.824cm for L and 1.6 for g and you yield 2.475 seconds. The period is 2.475 seconds.
How does accelaration due to gravity effect the time period of a simple pendulum?
Normally the acceleration of gravity is not a factor in the period of a simple pendulum because it does not change on Earth, but if it were to be put on another celestial body the period would change. As gravity increases the period is shorter and as the gravity is less the period is longer.
To determine the value of g acceleration due to gravity by means of an angular pendulum?
The period (time) of one swing of a pendulum is(2 pi) times the square root of (pendulum length / acceleration of gravity). There are three variables in this formula ... the length of the pendulum, the period of itsswing, and the acceleration of gravity. If you know any two of them, you can calculate thethird one. You want to use this method to measure gravity ? Fine ! Massage the formulaaround to this form Acceleration of gravity = (length of the pendulum) times (2 pi/period)2 then start measuring and swinging.The more accurately you can measure the length of your pendulum, from the pivotto the center of mass of everything that swings, and the period of its swing, and themore completely you can isolate everything from outside influences, like air currents,the more accurately you can calculate the acceleration of gravity, in the exact place whereyou run the experiment.
Why does accerlation due to gravity affect the period of a pendulum?
The period of a pendulum is give approximately by the formula t = 2*pi*sqrt(l/g) where l is the length of the pendulum and g is the acceleration (not accerlation) due to gravity. Thus g is part of the formula for the period.
Discussion of the measurement of gravity by a bar pendulum?
You can use a simple pendulum, measure how long one period takes, then use the formula for a pendulum, and solve for gravitational acceleration.
How do you find time period of pendulum?
T=2π√(L/g)where L is the length of the pendulum and g is the local acceleration of gravity.
How does the period of a pendulum vary?
The period depends only on the acceleration due to gravity and the length of the pendulum. Gravitational acceleration depends on the location on the surface of the earth: latitude, altitude play a part. Also, some pendulums are subject to thermal expansion and so the length changes. These factors do impact on the period of a pendulum.
What is the difference in period for a pendulum on earth and a pendulum on moon?
The period of a simple pendulum swinging at a small angle is approximately 2*pi*Sqrt(L/g), where L is the length of the pendulum, and g is acceleration due to gravity. Since gravity on the moon is approximately 1/6 of Earth's gravity, the period of a pendulum on the moon with the same length will be approximately 2.45 times of the same pendulum on the Earth (that's square root of 6).
Is the period of the pendulum influenced by the point from which it is released?
No Time period, T = 2π √(l/g) π - pi l - lenght of the pendulum g - acceleration due to gravity at the place
