3 x 3 x 5 x 7 = 315 The prime factors of 315 are 3, 5, and 7.
The prime factors of 315 are 3, 3, 5, and 7.
32 x 5 x 7 = 315
105, 210, 315, 420, and 525 have 3, 5 and 7 as prime factors. 105, 315, 525, 735 and 1575 have 3, 5 and 7 as their only prime factors.
The first step is to express these numbers as products of their prime factors: 315 = 3x3x5x7 660 = 2x2x3x5x11 The next step is to identify any common prime factors. In this case the common prime factors are 3 and 5. Multiply these and you get: 3x5 = 15 Thus the HCF of 315 and 660 is 15.
As a product of its prime factors: 3*3*5*7 = 315
The prime factors of 315 are 3, 3, 5, and 7.
315*3 = 945 does.
The factors of 315 are: 1 3 5 7 9 15 21 35 45 63 105 315 The prime factors are: 3 x 3 x 5 x 7
32 x 5 x 7 = 315
105, 210, 315, 420, and 525 have 3, 5 and 7 as prime factors. 105, 315, 525, 735 and 1575 have 3, 5 and 7 as their only prime factors.
The first step is to express these numbers as products of their prime factors: 315 = 3x3x5x7 660 = 2x2x3x5x11 The next step is to identify any common prime factors. In this case the common prime factors are 3 and 5. Multiply these and you get: 3x5 = 15 Thus the HCF of 315 and 660 is 15.
As a product of its prime factors: 3*3*5*7 = 315 or as 32*5*7 = 315
It's not 7 to the power of 2
105, 210, 315
As a product of its prime factors: 3*3*5*7 = 315
105, 210, 315, 420, 525
105, 210, 315, 420, 525