Math and Arithmetic

Algebra

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>>> 1:7 (or, if you like probability, 87.5%)

I disagree. There are four possible combinations of three tosses (where order does not matter):

HHH

HHT

HTT

TTT

Three of these combinations will show at least one head - only by throwing three tails will you not throw at least one head.

Thus, the probability of throwing at least one head in three flips is 75%.

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0If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8

Pr(3 flips at least one H) = 1 - Pr(3 flips, NO heads) = 1 - Pr(3 flips, TTT) = 1 - (1/2)3 = 1 - 1/8 = 7/8

For 3 coin flips: 87% chance of getting heads at least once 25% chance of getting heads twice 13% chance of getting heads all three times

As the question is "what is the probability of getting at least one head" the correct way to answer this is to ask what is the probability of not getting any heads and then subtract this from 1.The probability of not getting a head in 4 flips = 0.54 (i.e. 0.5 * 0.5 * 0.5 * 0.5) = 1/16.Therefore the probability of getting at least one head is 1 - 1/16 = 15/16.

The least of the three numbers is 199.

The least of the three integers is 26.

With two flips of a coin you can get two heads, two tails, a head and a tail, or a tail and a head. There are a total of four different possible outcomes, and three of them have at least one head. That's 3 out of 4, or 3/4ths. It's also 0.75 which is the probability of getting at least one head with two flips of a coin. Note that as we use the term probability here, it is zero (no chance it can happen at all), or one (it must happen), or something in between. A probability appears in the form of a fraction or decimal, and has no units attached to it.

-19 + -20 is -39, plus the next consecutive is -21, giving you -60. There is only one lowest set of consecutive integers that equals -60 so I don't get the at least part but this is your answer.

There's no such thing as one consecutive digit. There has to be at least two of them.When you count, consecutive digits are numbers that you name in a row, with nothing else between them.Examples:34 and 35 are consecutive. There's no counting number between them.97 and 98 are consecutive. There's no counting number between them.62 and 64 are not consecutive, because 63 comes between them.

The probability of obtaining 7 heads in eight flips of a coin is:P(7H) = 8(1/2)8 = 0.03125 = 3.1%

There are none...at least none that have evidence to their favor.

Zero. Any five consecutive natural numbers will contain at least one multiple of 2 and at least one multiple of 5, meaning that the product will be a multiple of 10.

Consecutive numbers can't both be multiples of 7. The LCM of consecutive numbers is their product. 14 and 15 are consecutive numbers whose LCM is a multiple of 7 that is greater than 200.

Yes because at least one of the consecutive numbers will be even, and if you times anything by an even number, the answer will always be even

Least common multiple of two consecutive numbers is always equal to their product. Since 27 & 28 are consecutive numbers, therefore LCM(27, 28) = 27 x 28 = 756.

yachtsman there is at least one other word with five consecutive consonants. I've yet to figure it out, so do share it if you got it.

There's at least one of each.

batter with the most strikeouts

No, because every other number in the number line is odd so therefore if you have any number of consecutive numbers you will have at least one odd number (if you're talking about consecutive numbers on a number line).

The LCM of two consecutive numbers is their product. The LCM of two consecutive multiples of 5 is their product divided by 5. Two consecutive numbers cannot be multiples of 5.

yes well i think at least

If you know that two of the four are already heads, then all you need to find isthe probability of exactly one heads in the last two flips.Number of possible outcomes of one flip of one coin = 2Number of possible outcomes in two flips = 4Number of the four outcomes that include a single heads = 2.Probability of a single heads in the last two flips = 2/4 = 50%.

All sides of a quadrilateral are consecutive, by definition.Not really. In the quadrilateral ABCD the sides AB and CD are opposite, but not consecutive. What is true for a quadrilateral is that any pair of sides that is opposite is not consecutive, and any pair that is not opposite is consecutive.The question asks what shape quadrilateral has 2 consecutive sides. If the question means "2 and only 2" consecutive sides the answer is that no such shape exists. If it means at least 2 consecutive sides then any quadrilateral fits the bill.If, as I suspect, the questioner meant 2 parallel sides, the answer is a trapezium.

The LCM of consecutive integers is their product. Consecutive integers will not both be multiples of seven.

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