Math and Arithmetic
Statistics

# What are the possible outcomes for 2 tosses of a coin?

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## Related Questions 2x2x2=8 possible outcomes. In general for n tosses there are 2^n outcomes. Each toss has 2 outcomes; so the number of outcomes for 3 tosses is 2*2*2 = 8 With 3 coin tosses, the possible outcomes are: HHH, HHT, HTH, HTT, THH, THT, TTH, TTT There are 8 possible outcomes and 3 of them have 2 heads. Thus: probability = 3/8 (= 0.375) 2 sides x 10 tosses, so your possibilities is 2^10 or 2x2x2x2x2x2x2x2x2x2 =1024 outcomes. It depends on the definition of an outcome. If you care about the order of the tosses, &lt;br /&gt; you get 2 possible outcomes per toss. Three tosses give you 2*2*2=8 possible outcomes. If you only care about the final number of heads and tails, there are 4 possible outcomes (3 heads, 2 heads and a tail, a head and two tails, or 3 tails). For a coin toss, there are 2 possible outcomes (heads or tails). For five tosses, therefore, there are 25 possible outcomes (25 = 32). However, this assumes that order is important (i.e. that HtttH is different to tHtHt). If you don't care what order the heads or tails fall in, there are only 6 outcomes.  The cube has 6 possible outcomes.The coin has 2 possible outcomes.There are 6 x 2 = 12 possible outcomes for a trialthat involves both the cube and the coin. The number of total outcomes on 3 tosses for a coin is 2 3, or 8. Since only 1 outcome is H, H, H, the probability of heads on three consecutive tosses of a coin is 1/8. There are 2 possibilities for each toss. Since the three tosses are independent (one trial does not affect the outcome of the other trials), there are 2 * 2 * 2 = 8 total possible outcomes. The outcomes are: HHH HHT HTH HTT THH THT TTH TTT  You think of each toss as having heads or tails, so there are two choices. If you toss the coin twice you have 4 choices HH, TT, HT and TH. The number of different coin tosses is 2^n ordered tosses and n+1 unordered. For example in two tosses, 2^2=4 ordered tosses if HT is different than TH and if HT is the same as TH then we have 2+1=3 different possible tosses. With 5 coin tosses there are 32 possible outcomes. 10 of these have exactly 2 heads, and 26 of these have 2 or more heads.For exactly two coins are heads: 10/32 = 31.25%For two or more heads: 26/32 = 81.25% There are 210 total possible outcomes from flipping a coin 10 times.There is one possible outcome where there are 0 heads.There are 10 possible outcomes where there is 1 head.So there are 210 - 11 possible outcomes with at least 2 heads.(1013) There are technically 8 possible outcomes if you are talking about the side of the coin it lands on. Each coin has 2 possible outcomes (landing on heads and landing on tails). To figure out the number of outcomes for all the coins you multiply the outcomes for all of the coins together: 2 X 2 X 2= 8. There is 2 outcomes for flipping the coin, and 6 outcomes for rolling the cube. The total outcomes for both are 2*6 = 12. There is 2 outcomes for flipping the coin, and 6 outcomes for rolling the cube. The total outcomes for both are 2*6 = 12. 75%. There are 3 possible ways of getting at least one tail from 2 tosses from a coin:Tail & Tail orHead & Tail orTail & HeadEach of these individual outcomes has a probability of 25% (e.g. the probability of getting a tail and then another tail is 25%). Adding the possible outcomes together gives you a total of 75%. There are 4 possible outcomes. There are 2 outcomes (heads or tails) on the first toss and 2 on the second toss. The possibilities are HH, TT, HT and TH.  Judy tosses a coin 4 times. draw a tree diagram showing the possible outcomes.What is the probability of getting at least 2 tails?  -- There are (2 x 2 x 2 x 2) = 16 possible outcomes of four tosses.-- There are three successful cases:H H T TT H H TT T H H-- So the probability is 3/16 or 18.75% . 4 : Each coin toss multiplies the generated outcome by two. The outcome for two tosses can be Heads (H) Tails (T), H H, T T or T H. As such, with three tosses the outcome can be H H H, H H T, H T H, T H H, T T H, T T T, T H T, H T T. We can define the number of outcomes as 2^n, where n is the amount of tosses. There are two outcomes for each coin and three coins; 2 x 2 x 2 = 23 = 8 outcomes.

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