There are 48 possible outcomes and I have no intention of listing them all.
They are all of the form CCCD
where C = H or T, and D takes the numeric values from 1 to 6.
24 possible outcomes.
I believe there would be 11 possible outcomes!
8 outcomes are possible in this situtation. You just have to multiply 4 by 2 to get the answer.
There are eight (8).
The possible outcomes areHH, HT, TH and TT.
Let's call one coin A and the other B. omes The possible outcomes for the coins are; A heads and B tails, A tails and B heads, A and B heads, A and B tails. That's four outcomes. The possible outcomes for a single die (as in dice) are six since a die has six faces, So four times six is twenty four possible outcomes.
If you know which coin is which, there are 16possible outcomes.If you're only counting the number of Heads and Tails, there are 5 .
Heads ( H ) Tails ( T ) HH , TT , HT , TH
There are eight possible outcomes: HHH, HHT, HTT, HTH, THT, TTT, TTH, THH.
The total number of outcomes is 2^5 = 32.
9, you just have to multiply for problems like this
Since each coin would have the outcome with Heads and Tails: Then among the 32 coins, we can have the possible outcomes from no Heads, 1 Head, 2 Heads, ....... , 31 Heads, 32 Heads. Therefore we would have 33 outcomes.
There are 25 or 32 possible outcomes can you get by tossing 5 coins.
Each coin has two possible outcomes, either Heads or Tails. Then the number of outcomes when all 4 coins are tossed is, 2 x 2 x 2 x 2 = 16.
When two fair coins are tossed, you have the following possible outcomes: HH, HT, TH, TT. So, at most implies that you get either i) zero heads or ii) one head. From the possible outcomes we see that 3 times we satisify the outcome. Thus, probability of at most one head is 3/4.
There are 23 = 8 possible outcomes.
Each coin can land in two ways.The die has 6 possible outcomes.So there are 2 x 2 x 6 = 24 possible outcomes for the whole experiment.Note that I am assuming the coins can be told apart - say the first coin and 2nd coin and that H and then T is different that T and then H. If not, then there are only be three outcomes for the coins-- 2 heads, 1 head or no heads and the total number of outcomes would be 3 X 6 = 18.
If you toss eight coins, there are 256 (28) different outcomes.
Use Pascal's Triangle Answer is 14641 different outcomes. - - - - 1 - - - 1 - 1 - - 1 - 2 - 1 - 1 - 3 - 3 - 1 1 - 4 - 6 - 4 - 1
Assuming the variable of interest is the face on top: H (= heads) or T (= tails), then they are the four possible outcomes: HH, HT, TH and TT.