Na+ and Cl-
H+ and I- are the spectator ions.
F=mv2+3 try it very useful equation
Mg(s) + H2SO4(aq) ==> MgSO4(aq) + H2(g) ... molecular equationMg(s) + 2H+(aq) + SO4^2-(aq) ==> Mg^2+(aq) + SO4^2-(aq) + H2(g) ... ionic equationMg(s) + 2H^+(aq) ==> Mg^2+(aq) + H2(g) ... net ionic equationSpectator is SO4^2- (sulfate ion).
The chemical formula CH3COCH3 2H corresponds to the compound acetone (CH3COCH3) with two hydrogen ions (2H) associated with it. The two hydrogen ions could indicate that the solution is acidic.
If the acid is a strong acid, it'll break into ions. If the acid is a weak acid, it won't break up. For instance H2SO4 is a strong acid. In water, It'll break it into 2H+ and SO4 2- An acid will dissociate it's H+ and whatever anion it was connected to. (ONLY IF IT IS A STRONG ACID!)
In the reaction (2H^+ + SO_4^{2-} + Ca^{2+} + 2I^- \rightarrow CaSO_4 + 2H^+ + 2I^-), the spectator ions are those that do not change during the reaction. Here, the ( H^+ ) ions and ( I^- ) ions are present on both sides of the equation and do not participate in the formation of the precipitate ( CaSO_4 ). Therefore, the spectator ions are ( H^+ ) and ( I^- ).
H+ and I- are the spectator ions.
F=mv2+3 try it very useful equation
To write the ionic equation for aluminum reacting with sulfuric acid, first write out the balanced chemical equation: Al + H2SO4 → Al2(SO4)3 + H2. Then, split the strong electrolytes (compounds that dissociate completely in water) into their respective ions: Al + 2H+ + SO4^2- → Al^3+ + 3SO4^2- + H2. Finally, cross out the spectator ions that appear on both sides of the equation to get the net ionic equation: Al + 2H+ → Al^3+ + H2.
KClO4 + H2SO4 → K2SO4 + HClO4. The net ionic equation for this reaction involves the dissociation of the strong electrolytes K+ and SO4^2- ions from K2SO4 and the H+ and ClO4^- ions from HClO4, while the spectator ions Cl^- from KClO4 do not participate in the reaction.
The net ionic equation is SO42- + Ca2+ CaSO4.
Mg(s) + H2SO4(aq) ==> MgSO4(aq) + H2(g) ... molecular equationMg(s) + 2H+(aq) + SO4^2-(aq) ==> Mg^2+(aq) + SO4^2-(aq) + H2(g) ... ionic equationMg(s) + 2H^+(aq) ==> Mg^2+(aq) + H2(g) ... net ionic equationSpectator is SO4^2- (sulfate ion).
2h + 2h + 2h = 6h
The chemical formula of sulfuric acid is H2SO4.
The net ionic equation for the given reaction is: 2H+ + SO4^2- + Ca^2+ + 2I- → CaSO4(s) + 2H2O. This equation highlights the ions that participate in the reaction and the formation of the solid calcium sulfate and water.
Good question. Someone else will probably have a better answer than me but this is what I learnt at school. The water molecules breakdown the bonds between the hydrogen Ions (2H^[+1]) from what is left over (SO4^[-2]). From my understanding water is just a catalyst in this reaction. Water H2SO4 --------> 2H^[+1] + SO4^[-2] However again someone probably has a better explanation than me
The chemical formula CH3COCH3 2H corresponds to the compound acetone (CH3COCH3) with two hydrogen ions (2H) associated with it. The two hydrogen ions could indicate that the solution is acidic.