If you mean: 32-10x+7y = 0 then as a straight line equation it is 7y = 10x-32
7y+5=-9... 7y must equal -14 therefore y must be -2
4X2+X3+3X+7Y+2X3 can only be simplified to 3X3+4X2+3X+7Y, because X3 and 2X3 are the only like terms.
8y - 38
That depends what you want it to equal at the end.
a + 7y
16+7y-8 = 7y+16-8 = 7y+8
-7y + 4y = -3y
39 - 7y = 18,-7y = 18 - 39-7y = -21-7y/-7 = -21/-7y = 3
4x^(2) + 28xy + 49y^(2) -> (2x)^(2) + 28xy + (7y)^2 Split into brackets ( 2x + 7y)(2x + 7y) If you applyuFOIL you will find toy come to '28xy'. The clue to this problem is to note that '4' ^ '49' are both squared numbers.
3y=7y+24.4 First, try to get all the y-terms on the same side of the equation. Easily done here by subtracting 7y from both sides 3y-7y=7y-7y+24.4 -4y=24.4 Now divide by -4 -4y/-4=24.4/-4 y=-6.1
-6y+3 = -7y+8 -6y+7y = 8-3 y = 5
7y + 4 - 4 - 9 = 7y - 9