Top Answer

It is the rated load that is applied to the circuit that the bulb is in. In laymen's terms, it is bulb brightness. The higher the wattage the brighter the bulb will glow.

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0V on a light bulb means volts. W means watts.

It means that the power consumption of the bulb is 40 watts.

It meas that the bulb uses 25 watts of electric power to run. Different types of bulb produce different amounts of light, with incandescent bulbs producing the least. A bigger proportion of the energy supplied to the compact fluorescent bulb is transferred to light and less wasted to the surroundings as heating.

By whatever do you mean? I mentioned an electric bulb the other day when mine went out. Shoot, you just mentioned it in your Question. Though Thomas Edison built the first working electric light bulb.

Is that the Ω (ohm) symbol you are referring to? An ohm is the unit of electric resistance.

An electrical watt is a measure of power. A 40 watt light bulb uses 40 watts of electrical power. It has a relative measure of twice the light output of a 20 watt bulb and one half the output of an 80 watt bulb. A 40 watt bulb uses 40 Joules of energy each second, or 40 watt-hours of energy each hour. In 1000 hours it uses 40 kilowatt-hours or Units of electrical energy.

it will take more than100 watts until the filament reaches operating temperature so perhaps a second to get as low as 100 watts . then 100Watts there after until 300 hours pass then 0 watts if you mean 100Watt hours then the answer is 1 hour and the hour will cost about a penny

The watts means nothing without the voltage.

Do you mean how many watts are used to make hot water? It varies, but a typical home electric hot water heater consumes about 4,500 watts. Industrial hot water heaters might use 20,000 watts or more! I have a little warmer that keeps my coffee warm as I type this, it consumes about 300 watts. Of course it only heats 6 ounces of water....

Watts are units of power. In simplified terms, power = voltage x current. So if a 120W light bulb is plugged into a 120V standard outlet, it will draw 1 Amp of current (120W = 120V x 1A).

Find out what your electric company charges you per kw hour. Now kw =1000 watts, so say you pay .12 per kw hour. A 100 watt light bulb is 1/10 of 1000 so divide .12 by 10. This would mean you pay .012 cents to run a 100w light bulb per 1 hour. Or .12cents for 10 hours

Not necessarily. More watts does mean more heat, but that does not absolutely equate to a higher temperature. A large professional iron (like a trouser press) will use more watts than a hand iron in order to reach the same temperature, just because it's bigger.

volts x amps = watts. That mean 15 vamps is 15 watts. If it is 15 amps at 120v then it is 1800 watts.

The formula you are looking for is W = I x E. Watts = Amps x Volts. W = 18 x 240 = 4320. Your dryer is rated at 4320 watts.However, just because your 240 volt outlet is rated at 18 amps does not mean that is what your appliance will draw.If the appliance is listed (by the manufacturer) as 1500 watts, then 1500 / 240 = 6.25, would mean that it will draw 6.25 amps at 240 volts.Note:Within the United States, most regular size electric dryers require a 240 volt, 30 amp power source. In addition to the electric heating element, there is the drum electric motor that must be factored in determining the wattage rating. That is the reason that it is best to use the manufacturer's nameplate rating for the answer to this question.

What do you mean like did he invent the light bulb because if you do mean that then yes he did invent the light bulb

Since the equation for watts is: Volts * Amps = Watts that would mean 12 Volts * 1 Amp = 12 Watts

most hairdryers on low use about 402 watts, and on high about 1440!!!

That it dissipates (i.e. uses up) 60 watts of electric power when in use. Since standard line voltage is roughly 120 volts, it draws roughly 0.5 amperes of current when in use. Note: CFL & LED lightbulbs have 2 ratings "equivalent" and "actual"; the "equivalent" is actually a measure of light output not power and tell the wattage of the incandescent lightbulb it is intended to replace, the "actual" is the actual wattage the bulb dissipates.

It isn't clear what you mean with "electric energy" if you don't mean an electric current.

Depends of what you mean by electricity. The 350 Watts says for each hour you have the light on you consume 350 Watt Hours of electricity. This is how you are charged by the Electric Company. Depending on where you live you may pay about 12 cents per 1,000 Watt hours or 1 Kilowatt hour. So your bulb costs about 4 cents per hour in electricity. To compute the current you need to know the voltage. Watts = Current x Volts.

In the U.S. all home light bulbs use 120 volts constantly. You may mean electrical power (watts) instead of voltage. If so, different light bulbs use different amounts of power. Typical general service incandescent light bulbs (ordinary old fashioned light bulbs) use about 1200 watts-hours (1.2 kilowatt hours) if burned all day and night. Twice that much for 100 watt bulbs. Compact fluorescent bulbs that produce a similar amount of light output use about 300 watts-hours (0.3 kilowatt hours) watts if burned all day and night.

No. Amperage is the current flowing down the conductor as voltage is a constant (relatively). As an example- a 120 volt light bulb is of course 120 volts but if it is 60 watts then it will draw .5 amps. a 100 watt bulb will draw around .8 ampsDifferent things.

if you mean lightning you have to buy it, if you mean electric there is no such thing

For parallel circuit, there's bronchus which mean the electric current'd have to choose which path to go. There's a main loop and more than one bronchus.If the bulb in one of the bronchus break down,the other bulbs would still light up. For series circuit,there's only one path for the electric current to flow through.If one of the bulb breaks down,the other'd go out as well. The electric current of evbery bulb in a series circuit is the same while the electric current of bulb in parallel circuit are not the same. The sum of the bronchus in a parallel circuit is equal to the main loop's.The more bulbs in a path,the more resistance will there be and less brighter it will be.A larger current will flow through the path with lower resistance so te brightness of the bulb of the bronchus will hace differences asc well.

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