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Instantaneous acceleration...

Slope of the tangent to a velocity time graph at any point is of the form

velocity/time=acceleration.

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1Instantaneous acceleration.

The tangent at a point on the position-time graph represents the instantaneous velocity. 1. The tangent is the instantaneous slope. 2. Rather than "average" velocity, the slope gives you "instantaneous" velocity. The average of the instantaneous gives you average velocity.

the slope of a tangent to the curve of a V vs T graph is acceleration at that point in time. the derivative of the function for the V vs T graph would be the function for acceleration at any given time

it measures the magnitude of acceleration, but it can't tell you the direction of the acceleration.

The slope of the tangent line in a position vs. time graph is the velocity of an object. Velocity is the rate of change of position, and on a graph, slope is the rate of change of the function. We can use the slope to determine the velocity at any point on the graph. This works best with calculus. Take the derivative of the position function with respect to time. You can then plug in any value for x, and get the velocity of the object.

Tangent of the slope at any point = velocity

Velocity of the Particle -PRAKHAR

The average acceleration can be obtained by finding the slope of the graph. The instantaneous acceleration is found by drawing a tangent to a particular point on the graph (instant) and finding the slope of than tangent.

No, it is instantaneous acceleration.

The slope (technically, the slope of the tangent at each point) of a distance-time graph gives the instantaneous velocity. Therefore, if the graph has a constant slope - i.e. it is a straight line - then that indicates a constant velocity (zero acceleration).

It is the instantaneous velocity, if it were a graph with velocity over time, then it would be acceloration

Simply put, a velocity time graph is velocity (m/s) in the Y coordinate and time (s) in the X and a position time graph is distance (m) in the Y coordinate and time (s) in the X if you where to find the slope of a tangent on a distance time graph, it would give you the velocity whereas the slope on a velocity time graph would give you the acceleration.

Take a tangent at the point where you want the slope. Then the slope of the graph at that point is the slope of the tangent, which is found by taking another point on the tangent and then taking the change in y between the two points and divid it by the change in x.

Yes, the derivative of an equation is the slope of a line tangent to the graph.

You can't determine velocity from that graph, because the graph tells you nothing about the direction of the motion. But you can determine the speed. The speed at any moment is the slope of a line that's tangent to the graph at that moment.

The slope of the position/time graph is the magnitude of velocity, i.e. speed.It doesn't tell you anything about the direction of velocity. If the direction ofvelocity is changing, the slope of the graph doesn't necessarily change.If the magnitude of velocity (speed) changes, then the slope of the graph changes.If speeding up, the slope of the graph increases, and the graph curves upward.If slowing down, the slope of the graph decreases, and the graph curves downward.

The slope of a velocity versus time graph is the acceleration.

Use the four-step process to find the slope of the tangent line to the graph of the given function at any point.

The rate of acceleration is a measure of the change of the velocity of an object with time. On a graph of velocity versus time, it is represented by the slope of the line so graphed. If velocity is changing in time, the object described is being accelerated. The greater the slope of the graph, the greater the change of velocity per unit of time and the greater the acceleration of that object. true

if the segments on the disp vs time graph are straight lines, you merely measure the slope of those lines; the velocity is the slope of the lineso if the disp vs time graph shows a straight line of slope 3 between say t=0 and t=4, then you know the object had a constant speed of 3 units between t=0 and t=4;if the disp vs time graph is curved, then you need to find the slope of the tangent line to the disp vs time curve at each point; the slope of this tangent line is the instantaneous speed at the time, and with several such measurements you can construct your v vs t graph

The slope of the velocity graph.

Yes it does. Velocity = Displacement / Time. On a graph of displacement vs time, the slope is the velocity. Steeper slope = higher velocity, flatter slope = lower velocity.

The slope of a position-time graph is velocity. The slope of a velocity-time graph is acceleration. Displacement also can be determined by determining the area under the slope of a velocity-time graph.

You find the slope of the tangent to the curve at the point of interest.

the slope at any point on the graph is the acceleration

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