33*3=99
3*33=99
21+35+43=99
Take two 9s and make them a fraction like this 9/9. Then put the other two 9s together to make 99 and you get 9/9+99=100. Because 9/9=1 so it becomes 1+99=100.
3 times 33 equals 99.
99
498
Applying the rules of BODMAS, whereby the actions of multiplication and division are carried out before the actions of addition and subtraction, 99 + (8 x 3) = 99 + 24 = 123.
First add all the addition together and add all the subtraction together. Then there will be the total addition and the total subtraction. Subtract the total subtraction from the total addition.99+98-97+96-95+94-93+92-91+90=(99+98+96+94+92+90)-(97+95+93+91)=569-376=193
21+35+43=99
Take two 9s and make them a fraction like this 9/9. Then put the other two 9s together to make 99 and you get 9/9+99=100. Because 9/9=1 so it becomes 1+99=100.
3*33 ■
Number 99 is 100 - 1 = IC with 1 before 100 for subtraction
2x-3 = 10x-99 start by moving the terms with variables (x) on one side of the equal sign, and the constants (regular number, with no variables) to the other side. Do this by addition and subtraction. 2x-3 = 10x-99 +99 +99 now you have 2x +96= 10x now get both of the variables on the right side 2x+96 = 10x -2x -2x now you have 96 = 8x now solve for x by dividing each side by 8 96/8 = 8x/8 x= 12
3 times 33 equals 99.
-99
This equals 198.
44*99 = 44*(100-1) = 44*100 - 44*1 (using the distributive property) = 4400 - 44 = 4356
100-1 101-2 102-3