Fluorine...
it has seven valence electrons and really wants to achieve noble gas configuration (8 out of 8 possible valance electrons). It already has seven and since it is so close to eight, it is very attached to them. It refuses to give them up easily. The more an element "wants" it's electrons the higher ionization energy it will have.
http://www.800mainstreet.com/4/0004-002-Periodic.html
Krypton is the noble gas that has four energy levels.Also they are located on the side of the elment for an example Kryptons energy levels are 2,8,18,8.
Krypton is the noble gas that has four energy levels. Also they are located on the side of the elment for an example Kryptons energy levels are 2,8,18,8.
The Noble Gasses (also called the Inert Gasses.)
helium due to its smallest size.
the lowest ionization energy in IA :hydrogen ,lithiun ,sodium and potassium
Core electrons. Probably the 1s level would require the most ionization energy to pull these electrons.
The first ionization energy decrease from top to bottom for the noble gas family.
This is the alkali metals family; the ionization energy is lower for these chemical elements.
Ionization can have any number of causes, resulting in any number of ionization states ranging from ±1 to ±(atomic number) for any given atom. In the given context, however, I would assume the actual question intended is, "What is the preferential ionic state of ionically bonded atoms in the VIA periodic family?" The answer to this question is -2.
the lowest ionization energy in IA :hydrogen ,lithiun ,sodium and potassium
Core electrons. Probably the 1s level would require the most ionization energy to pull these electrons.
The first ionization energy decrease from top to bottom for the noble gas family.
This is the alkali metals family; the ionization energy is lower for these chemical elements.
Ionization can have any number of causes, resulting in any number of ionization states ranging from ±1 to ±(atomic number) for any given atom. In the given context, however, I would assume the actual question intended is, "What is the preferential ionic state of ionically bonded atoms in the VIA periodic family?" The answer to this question is -2.
The element is 'argon' and belongs to noble gas family.
An element with two electrons in its highest energy level is probably an alkaline earth metal. More specifically, it is likely magnesium or calcium, as these are the most common alkaline earth metals.
Neon
ionization energies (IE) have to do with things called ions. Ions are atoms which have gained or lost electrons. The ionization energy is the amount of energy it takes to detach one electron from a neutral atom. Some elements actually have several ionization energies. When this is the case, we refer to them as the "first ionization energy" or 'I', "second ionization energy" or 'I2', and so on. Notice that the energy variable follows Ii where i is the orbital from which the electron is lost. Ionization is endothermic meaning that the atom or molecule increases its internal energy (takes energy from an outside source).
It decreases as the atom radius gets larger, so it decreases from top to bottom.
You question is not very clearly stated but I think I know what you are asking. As you go down the column of any family of elements in the periodic table, you move to increasingly heavier and larger atoms. Their outer electrons are therefore farther from the nucleus, and even though the nucleus is larger and has a larger positive charge, the increased distance is the predominant influence, making the outermost electrons less tightly bound, and therefore more easily ionized, with a lower ionization energy.
Boron and Oxygen Family