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x + x + 2 + x + 4 +x + 6 = 336

4x + 12 = 336

4x = 324

x = 81

81,83,85, 87

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Q: What four consecutive odd integers have a sum of 336?
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4 consecutive integers whose sum is 336?

There are four consecutive odd integers: 81, 83, 85 and 87.


Find four consecutive odd integers whose sum is 336?

The integers are 81, 83, 85 and 87.


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Any odd integer can be represented as 2n+1, where n is any integer. The integers, starting with one, always proceed as odd, even, odd, even, etc. Therefore, a consecutive odd would be two more than the first. So 2n+1, 2n+3, 2n+5, and 2n+7 summed to 336. Simple algebra gives n=40, and the four numbers as 81, 83, 85, and 87.


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