The volume decrease only when the external pressure increase.
Polar gases would have some mutual attraction and there by observe a decrease in volume so the volume of the balloon would decrease.
Boyle's Law which relates volume to pressure.
The volume decrease.
Decrease the pressure of the surrounding environment. Thus, the force acting on the balloon from the outside decreases, allowing the air pressure that creates a force inside the balloon to have less of a counteracting force.
The ballon will start to desend as the volume created by the heat will decrease, thus reducing the balloons capacity to stay in the air.
Decrease
Polar gases would have some mutual attraction and there by observe a decrease in volume so the volume of the balloon would decrease.
the balloon's volume would decrease!!!
the balloon's volume would decrease!!!
the balloon's volume would decrease!!!
Yes. When you squeeze the balloon, you cause the volume to decrease. Since density is determined by dividing mass by volume, a decrease in volume will cause an increase in denisty.
Compression
it will shrink because the volume will decrease
Compression
The pressure of the gas would rise. Explain? OK, Blow up a balloon and tie the end. Decrease volume of the container (step on balloon). Balloon explodes (Pressure rose)
Boyle's Law which relates volume to pressure.
Nothing happens to the mass of the balloon. Mass is conserved, so the temperature of the balloon will not affect it's mass. Mass can be thought of the amount of "stuff" that makes up a balloon. It can be obtained by adding up the mass of all the molecules of rubber in the balloon. Obviously, putting the balloon in a warm room will not change the number of molecules in the balloon, therefore the mass stays constant. The volume of the balloon will probably increase. Because volume increases but mass remains constant, the density of the balloon would decrease. D = m/v