Acceleration is a net force that is inversely dependent on mass, therefore if an object mass increases ,acceleration decreases
Acceleration increases as force increases.
the cceleration of the object because the second the of newton explains the relation between force and acceleration and the two happen to bne directly proportional so if the acceleration increases so does the force or vice verca.
When mass increases, the force increases (f=ma) and the acceleration decreases (a=F/m).
Yes, the acceleration of an object is directly proportional to the net force acting on it. this means that, as the net force acting on the object increases, the acceleration of the object increases; thus, the function forms a linear pattern.
Since the force of gravity is directly proportional to mass, then increasing the mass of an object increases the force of gravity it produces.Since accceleration = force/mass, then increasing the mass of an object means it will have a smaller acceleration for the same force (or alternatively that you need more force to produce the same acceleration).
Acceleration is a net force that is inversely dependent on mass, therefore if an object mass increases ,acceleration decreases
Acceleration increases as force increases.
the cceleration of the object because the second the of newton explains the relation between force and acceleration and the two happen to bne directly proportional so if the acceleration increases so does the force or vice verca.
The acceleration increases.
its acceleration will be increased
its acceleration will be increased
If you increase the force on an object acceleration increases . As F = m*a, where F = Force , m = mass of the object & a = acceleration
The Acceleration Increases.
If you increase the force on an object acceleration increases . As F = m*a, where F = Force , m = mass of the object & a = acceleration
Acceleration is a net force that is inversely dependent on mass, therefore if an object's mass decreases, acceleration increases.
When mass increases, the force increases (f=ma) and the acceleration decreases (a=F/m).
It increases