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When the voltage is increased across a metal film resistor, the current flow will also increase. Ohm's law states that the current flowing through a resistor is directly proportional to the voltage across that resistor.

I = V/R

Let us assume an initial voltage drop across a 4.99K ohm metal film resistor is 5V. The current flow through the resistor is calculated to be:

I = 5/4990

= 0.001 Amps or 1 mA

If that voltage were to say double to 10V:

I = 10/4990

= 0.002 Amps or 2 mA

Using these values it is also possible to calculate the power dissipated by the resistor.

P = I*V

= 0.002 * 10

= 0.02 Watts

This power calculation determines the minimum physical case size needed for the resistor to function within these conditions. Anything smaller, the resistor will fail.

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Q: What happens to the current flowing through a metal resistor when the voltage across is increased?
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