Displacement: Grows with time, at an increaing rate.
Velocity: Grows with time, at a constant rate.
Acceleration: Greater than zero, remains constant with time.
Displacement and acceleration are zero at the instant the mass passes through its "rest" position ... the place where it sits motionless when it's not bouncing. Velocity is zero at the extremes of the bounce ... where the expansion and compression of the spring are maximum, and the mass reverses its direction of motion.
No, acceleration is the rate of increase or decrease in the velocity of an object. An object at high velocity will have zero acceleration if its velocity is not changing. A slow moving object will have high acceleration if its velocity is changing quickly. Answer: The above is correct, but if you have... say a fast moving object in the earth's atmosphere, like a space shuttle entering the earth atmosphere, the faster it goes, the more force will be applied to it to slow it down by the air it has to pass through. So, its possible, that, if you give something a large velocity, like a base ball for example, it will be subject to larger resistance to motion force, which is proportional to the velocity squared and will consequently accelerate more in the opposite direction of motion.It is very important not to get velocity and acceleration mixed up though. Velocity is the rate of change of displacement; acceleration is the rate of change of velocity. Simply having a high velocity in the absence of an atmosphere will not cause a greater acceleration by itself.
As light's velocity is constant through any given medium, its acceleration is zero inside that medium.
The speed of the roller coaster will be limited by various sources of resistance such as that of its wheels on the rails and its passage through the air. If we ignore these we can get an upper bound on the vehicle's speed. You have probably seen the equation that relates final velocity to initial velocity, acceleration and displacement:v2 = u2 + 2aswhere v is initial velocity, u is initial velocity, a is acceleration and s is displacement. In this case acceleration is g, gravitational acceleration, and u is zero.We have : v2 = 2 . 9.80665 m.sec-2 . 100 m = 1961.33 m2.sec-2Then v = sqrt (1961.33) m.sec-1 ~= 4.43 m.sec-1
Never.Average velocity is total displacement (final position minus initial position) divided by the total time: vave = (xf-xi)/tAcceleration is the rate at which your velocity is changing or change in velocity over time: a= (vf-vi)/tThese two quantities may have the same numerical value but will never have the same units.Average velocity for a trip can equal instantaneous velocity at a certain point during the trip, however, at any time during a trip in which the velocity is constant or at half way through the total time of a trip where the acceleration is constant.
if by 'you', you mean 'u' then u is the initial velocity v is the final velocity. you need to know the initial velocity in trajectory question (motion of an object through the air) to find height, acceleration, time etc.
The averagevelocity v of an object moving through a displacement during a time interval is described by the formula:
As, in the velocity-time graph, curves passes through zero means 'when time is zero velocity is zero'. Velocity is time derivative of displacement. So displacement is maximum or minimum when time is zero in position-time graph.
acceleration is calculated through this formulaA = F/m where a is acceleration, F is Force, m is MassORthere is some calculus involved in solving and acceleration question because instead of dealing with velocity over time, you are in fact working with the Change in Velocity over time.a = Δv/Δt = (vfinal - vinitial) / (tfinal - tinitial)Wrong Answervelocity divided by time = acceleration
Constant velocity is, well, constant. To measure it, measure the displacement through a given or fixed period of time. You'll have distance and time. Distance per unit time is speed. Distance per unit time (speed) with a direction vector is velocity. Velocity is speed in a given direction. If something is moving at constant velocity, it is moving at a constant speed in one direction. No changes in speed (no positive or negative acceleration, or, said another way, no acceleration at all), and no change in direction or heading.
Yes...acceleration is the rate of change of velocity with time.....therefore when velocity is zero..definitely acceleration is zero This is not exactly true; at an instant in time the acceleration can be non-zero while the velocity is zero. However, this would change the velocity to non-zero after any amount of time. An example of this is when you throw a ball into the air: at it's highest point, the velocity is zero (it changes from going upward to going downward, passing through zero for an instant). However the acceleration is downward the entire time.
Yes, think about this; when you through a ball up in the air the velocity will be positive since its going up but the acceleration will be -9.8 since it is going against gravity.
The slope of a straight line tells the rate at which your variables are changing. In this case, it tells you how your velocity is changing over time, which in physics is how we define acceleration. If you graph the velocity of an object vs time when it is falling through the air, it gives to the acceleration due to gravity because that is the acceleration all objects fall at.
Yes, it is possible. For example, if you through an object up, its velocity would initially be in the "up" direction, but its acceleration would be in the "down" direction.
Perhaps you mean terminal velocity. This is the maximum velocity reached by an object falling to the ground when the acceleration due to gravity is matched by the drag resistance of the air through which it is falling.
The nature of displacement-time graph is parabolic if the acceleration is constant(uniform). When acceleration is constant, displacement is directly proportional to the square of time which results into a parabolic structure of graph.
Mass by itself has no effect on velocity. In terminal velocity (velocity of an object falling through a fluid) the mass tovolume ratio (density) can change the final velocity at any given medium density, but in acceleration in a vacuum there is no impact from mass on velocity.
If the velocity equals zero, the acceleration is also zero because the velocity hasn't changed, thus, the particle isn't accelerating anywhere. This is not exactly true; at an instant in time the acceleration can be non-zero while the velocity is zero. However, this would change the velocity to non-zero after any amount of time. An example of this is when you throw a ball into the air: at it's highest point, the velocity is zero (it changes from going upward to going downward, passing through zero for an instant). However the acceleration is downward the entire time.
Yes. Consider a skydiver in freefall. Fairly quickly the skydiver will reach terminal velocity (the speed at which their acceleration from gravity is cancelled out by the resistance of the air through which they are falling). At terminal velocity the skydiver has non-zero velocity (about 56m/s or 200km/h) but zero acceleration (because their velocity is not increasing). In a vacuum, where there is no air resistance, there is also no terminal velocity. Because there is no force acting against acceleration an object will continue to accelerate provided its source of acceleration continues to be applied. It is worth noting that an object cannot use this rule to exceed the speed of light because as the speed of light is approached the relative time for the object slows. On earth, however, or indeed in any similar environment, an object can certainly have zero acceleration and non-zero velocity.
Yes, but only briefly, not permanently. At an instant in time the acceleration can be non-zero while the velocity is zero. However, this would change the velocity to non-zero after any amount of time. An example of this is when you throw a ball into the air: at it's highest point, the velocity is zero (it changes from going upward to going downward, passing through zero for an instant). However the acceleration is downward the entire time.
a vel time graph passing through d origin.... at t=0.. vel=o.. bt acceleration not=0..
No starting velocity was given, so I can't give a correct answer, but I can answer part of the question. Given an acceleration and a time through which an object accelerates, you can determine the change in velocity. Acceleration is just the change of velocity over a period of time. Since we have an acceleration of -3.1 meters per second squared, acting for two seconds, we have a change in velocity of -6.2 meters per second. Take the original velocity and subtract 6.2 meters per second to get the answer.
Velocity= Displacement over time. The mass on your scooter is relevant to the mass of you, let's say 200 kg. If you want to keep a constant speed of your scooter, it means that you want it to have negative acceleration, which means that you don't put a change in velocity. Keep your head low, close your eyes, and ride through a wall. You'll get the hang of it after a while
It was 6 radians per second. Angular acceleration = -3 radians per second2 Initial angular velocity = 6 radians per second. Final angular velocity = zero. Average angular velocity = 3 radians per second. Angular displacement in 2 seconds = 3 x 2 = 6 radians.
Initially, about 9.8 (m/s)/s, diminishing through air friction to 0 at terminal velocity.