What happens to the pressure if the temperature in K is doubled?

Answer 1

The initial pressure is halved. Use Boyle's law that relates pressure & volume at a constant temperature.

P1V1 = P2V2

In this case the V1(initial volume) is doubled so V2 = 2V1

P2 = P1V1/V2 = P1V1/2V1

P2 = (1/2)*P1

Answer 2

For an ideal gas, per the Ideal Gas Law, pV = nRT, if temperature doubles, then pressure doubles.

Answer 3

pv=nrt

if temp and pressure double, the equation is sound, and volume remains constant.

Answer 4

PV=nRT, so P=nRT/V for an ideal gas, so if the volume is doubled and the temperature is halved, the pressure remains constant.

Answer 5

Pressure doubles too. Temperature and pressure share a direct relationship (this is called Gay-Lussac's Law.)

Answer 6

Assuming the volume remains constant, doubling the temperature will increase the pressure by 2 times, i.e. it will also double.

Answer 7

Assuming the volume of the container and the amount of product in it remain constant, if temperature doubles pressure will also double.

Answer 8

The volume is decreased to 1/2.

Answer 9

The pressure is also doubled.

Answer 10

EXPLOSSION