It decreases. As the dimensions increase by a number, the surface area increases by the same number to the power of 2, but the volume increases by the same number to the power of 3, meaning that the volume increases faster than the surface area.
As volume increases surface area increase, but the higher the volume the less surface area in the ratio. For example. A cube 1mmx1mmx1mm has volume of 1mm3 surface area of 6mm2 which is a ration of 1:6 and a cube of 2mmx2mmx2mm has a volume of 8mm3 and surface area of 24mm2 which is a ratio of 1:3.
Volume increases more rapidly than surface area.
the volume gets larger but the surface area gets smaller
The larger the cell the lower the surface area to volume.
It generally decreases.
Yes.
As the surface to volume ratio increases the rate of in exchange increases too.
The surface area-to-volume ratio.
When cells get smaller, the volume (as well as mass) decreases faster than the surface area so the surface:volume increases. Cells with a high surface:volume are more effective in receiving nutrients through diffusion. A cell (assume perfect sphere) with radius 2 has a surface area of 16pi and volume of 32pi/3. A cell with radius 3 has a surface area of 36pi and volume of 108pi/3. Also relatively speaking, volume can be thought of as y=x3 and surface area as y=x2. When there is a change in x, the change is more dramatic in the volume, so small cells have high ratios and large cells have low ratios.
The cell's ratio of surface area to volume would decrease. However, this scenario is extremely unlikely.
Yes.
As the surface to volume ratio increases the rate of in exchange increases too.
As the cell grows larger the ratio of surface area to volume increases. Larger cell = more volume for the amount surface area.
The cell's ratio of surface area to volume would decrease if its volume increases more rapidly than its surface area.
As volume increases surface area increase, but the higher the volume the less surface area in the ratio. For example. A cube 1mmx1mmx1mm has volume of 1mm3 surface area of 6mm2 which is a ration of 1:6 and a cube of 2mmx2mmx2mm has a volume of 8mm3 and surface area of 24mm2 which is a ratio of 1:3.
The surface area-to-volume ratio.
As a cell increases in size the volume increases much faster than the surface area. The possible answer is C.
When cells get smaller, the volume (as well as mass) decreases faster than the surface area so the surface:volume increases. Cells with a high surface:volume are more effective in receiving nutrients through diffusion. A cell (assume perfect sphere) with radius 2 has a surface area of 16pi and volume of 32pi/3. A cell with radius 3 has a surface area of 36pi and volume of 108pi/3. Also relatively speaking, volume can be thought of as y=x3 and surface area as y=x2. When there is a change in x, the change is more dramatic in the volume, so small cells have high ratios and large cells have low ratios.
The ratio decreases.
The ratio decreases.
If the length of the cube's side is 'S', then the surface area is 6S2 and the volume is S3 .The ratio of surface area to volume is 6S2/S3 = 6/S .This number is inversely proportional to 'S'. So as the side increases ...causing the volume to increase ... the ratio does decrease, yes.
it callapses