Californium-251 decay by alpha emission.
Curium: (Symbol Cm, At No 96, At Wt 247, Melt Pt 1337ºC, Boil Pt 3110ºC) is named after Pierre and Marie Curie.
A good candidate would be curium 247 (247Cm), which has a half-life of 1.56 × 107 years. That's 15,600,000 years (15.6 million years).
Uranium-238 is a natural isotope of uranium with the mass 238,050 788 247 ± 0,000 002 044 u.a.
I believe you would have to use the formular PV=nRT for this problem. First convert n from kg to moles, knowing that Neon is 20.1797 g/mol: (5 kg x 1 mol) / .0201797 kg = 247 mols Next, identify all the variables: P = ? V = 200-L T = 300 K n = 247 mols R = 0.08206 (L*atm)/(K*mol) Now plug the values into the formula: PV = nRT therefore P = nRT /V P = (247 mols)(0.08206 (L*atm)/(K*mol))(300 K) / 200-L = 30.4 atm
Atomic mass = 36.453g/M 0.43M/L x 0.247L = 0.10621M 0.10621M x 36.453g/M = 3.872g
IUPAC consider the atomic weight of curium 247; this is the mass of the isotope 247Cm, the curium isotope with the longest half life.
The atomic number if curium (Cm) is 96 and its approximate atomic mass is (247). The () denotes that the exact mass is not confirmed, as curium is radioactive and unstable. So it is not easy to calculate the exact mass of all its isotopes.
Curium is an artificial chemical element. Number of neutrons = Atomic mass of an isotope - atomic number of the isotope The atomic number of curium is 96; and atomic mass is 247 so no of neutrons is 151.
251Cf --> 247Cm + 4He 247Cm --> 243Pu + 4He 243Pu --> 243Am + e- 243Am --> 239Np + 4He 239Np --> 239Pu + e- 239Pu --> 235U + 4He 235U --> 231Th + 4He 231Th --> 231Pa + e- 231Pa --> 227Ac + 4He 227Ac --> 223Fr + 4He, 227Th + e- 223Fr --> 219At + 4He, 223Ra + e- 227Th --> 223Ra + 4He 219At --> 215Bi + 4He, 219Rn + e- 223Ra --> 219Rn + 4He 215Bi --> 215Po + e- 219Rn --> 215Po + 4He 215Po --> 211Pb + 4He 211Pb --> 211Bi + e- 211Bi --> 207Tl + 4He, 211Po + e- 207Tl --> 207Pb + e- 211Po --> 207Pb + 4He 207Pb: stable
Practically none, though it seems plausible that trace amounts of Cm-247 exist in uranium ore.
42 20 Ca
Curium: (Symbol Cm, At No 96, At Wt 247, Melt Pt 1337ºC, Boil Pt 3110ºC) is named after Pierre and Marie Curie.
A good candidate would be curium 247 (247Cm), which has a half-life of 1.56 × 107 years. That's 15,600,000 years (15.6 million years).
Isotopes of curium have masses between 232 and 252. It is your choice to subtract 1oo from (232 to 252) and to found an isotope. I have the same homework!!! The answer is calcium. - Linz The most important isotope of curium has an atomic weight of 247; 247-100 is 147. This is the mass of an important isotope of promethium.
curiumHope this helped :)
The reciprocal of -247 is -1/247(Because -247 = -247/1
247% = 247/100