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CaCl2(aq) + Pb(NO3)2(aq) ===> Ca(NO3)2(aq) + PbCl2(s) so a precipitate of PbCl2 (lead chloride) will form. The fact that equal volumes of 0.2 M are mixed indicates that all of the Pb^2+ and all of the Cl^- will precipitate out of solution leaving only Ca^2+ and NO3^- left in solution.

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The percent by mass of Ca in CaCl2 is equal to?

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What is the mass of 0.89 mol of CaCl2?

To find the mass of 0.89 mol of CaCl2, you need to multiply the molar mass of CaCl2 by 0.89 mol. The molar mass of CaCl2 is 110.98 g/mol. Therefore, the mass of 0.89 mol of CaCl2 would be 98.882 g.


How many grams of CaCl2 equal 3.40 moles of CaCl2?

The molar mass of CaCl2 is 110.98 g/mol. To find the mass of 3.40 moles of CaCl2, you would multiply the number of moles by the molar mass: 3.40 moles x 110.98 g/mol = 377.192 g. Therefore, 3.40 moles of CaCl2 is equal to 377.192 grams of CaCl2.


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