What happens when malachite is dissolved in sulphuric acid?
Malachite is mostly contained of Copper carbonate, which is why its green in colour. It dissolves in sulfuric acid to give Copper sulfate, Carbon dioxide and Water.
CuCO3 + H2SO4 ----> CuSO4 + H2O + CO2
The product is Disulphuric acid. Its other name are Pyrosulfuric acid, Fuming sulphuric acid and Oleum. Its formula is H2S2O7 . Its salts are called Disulphates and contain the S2O7-2 anions. It decomposes in water to produce Sulphuric acid. Sulphuric acid + Sulphur trioxide ----> Disulphuric acid H2SO4 + SO3 ----> H2S2O7 (already balanced equation)
0.01 N sulphuric acid means 0.01 equivalents dissolved in 1 litre of water. Nomality = Molarity x n-factor => molarity= normality /n-factor molarity = 0.01/2=0.005 M [ n-factor of sulphuric acid is 2] Thus, a 0.01N solution of sulphuric acid contains 0.005 moles of sulphuric acid in 1 litre. 0.005 moles=0.005 x 98 = 0.49 grams. => Dissolve 0.49 grams of sulphuric acid in 1 litre water to make a 0.01N solution