Nothing. Copper is lower than iron in the electromotive series and will not replace the iron in the iron nitrate solution.
We have just done a lab about single displacement reactions. Most students got a reaction in which the blue solution of copper (II) nitrate turned black/bronze color. Fe is above Cu in terms of reactivity series. Therefore, it will displace copper.
The iron which is a more electrochemically active metal gets plated with copper and iron sulfate is formed
When Iron metal is dipped into a solution of copper sulfate a REDOX reaction occurs in which the Copper is reduced (gains electrons) and the iron is oxidised (loses electrons). When this happens, the iron metal becomes iron ions and the copper ions in the solution become copper metal. Cu2+(aq) + 2e- --> Cu(s) Fe(s) -->Fe2+(aq) + 2e- This occurs because the iron is a more active metal than copper, and as a general rule of thumb, a more reactive metal will displace a less reactive metal from solution. This principle underlies the action of the sacrificial electrode.
When an iron nail is placed in a copper sulphate solution, iron displaces copper from copper sulphate solution forming iron sulphate, which is green in colour.Therefore, the blue colour of copper sulphate solution fades and green colour appears.
When an iron nail is dipped in the copper sulfate solution then iron displaces copper from the copper sulfate because iron is more reactive than copper.
the solution turns green and the nails develop a brown deposit which is copper. the iron displaces the copper in the copper sulphate solution. This is because iron is more reactive than copper.
Iron nitrate and metallic copper.
The products are iron (II) nitrate and copper.
No. Iron is a more reactive metal than silver, so the iron will replace the silver in the silver nitrate solution, forming an iron nitrate solution and solid silver. Eventually, the iron container will be gone, its atoms having gone into the iron nitrate solution.
It forms a brown ring just above the copper solution.
We have just done a lab about single displacement reactions. Most students got a reaction in which the blue solution of copper (II) nitrate turned black/bronze color. Fe is above Cu in terms of reactivity series. Therefore, it will displace copper.
The iron which is a more electrochemically active metal gets plated with copper and iron sulfate is formed
Iron is more reactive than copper, so the copper precipitates out of the solution by sticking to the iron. For example, if you have a test tube with a solution of copper (II) sulfate and put an iron nail into it, the iron will react with the solution to form iron (II) sulfate and the copper will come out of the solution and stick to the iron.
what iron is present in copper nitrate
A brown layer of copper gets deposited on iron nail. This change is due to a chemical reaction between copper sulphate and iron. Also the colour of the solution changes from blue to green due to the formation of iron sulphate. This reaction can be represented by the following equation: Copper sulphate + Iron = Iron sulphate + Copper solution (CuSO4) + (Fe) = (FeSO) + (Cu)
Iron (II) nitrate and elemental copper.
Iron nitrate and copper. Fe + Cu(NO3)2 -> Fe(NO3)2 + Cu