Answer: it will burn out
**Explain:**The same current flows through each part of a series circuit. If the circuit is broken at any point there won't be any current that will flow. In this case, if one of the bulbs blew out, the other bulb would not be able to light up because the flow of electric current would have been interrupted.
If the bulb is remove from series circuit, the loop is break or no current flow. And all the bulb in off state..
Current will cease to flow since removing the light bulb opens the circuit.
In a series circuit, each bulb is needed to complete the circuit, so if one bulb breaks, the circuit is broken and all bulbs will turn off. Like some of the older Christmas lights would do.
It goes out.
When a light bulb is connected in a series circuit and it burns out, the circuit is interrupted and everything connected in the curcuit does not have current flowing through them.
If you removed one bulb in the series circuit the other bulb will go out because series only go through one path of electricicty.
All the bulbs will go out. In a series circuit, the current at all points is the same. This is Kirchoff's Current Law. If you loosen or remove a bulb in a series circuit, the current at that bulb becomes zero, and by Kirchoff's Current Law, the current in every part of the circuit also becomes zero.
it should become dimmer
In that case, the entire circuit won't work.
All of the light bulbs in the series circuit would go out.
If you unscrewed any bulb in the circuit it would turn all of the bulbs off.
When we remove one light bulb from a socket in a series circuit the other all bulb switch off because they are connected in series.CommentIt's worth mentioning that the full supply voltage then appears across the empty lamp-holder, providing a shock hazard.
All the bulbs in the series goes out, as no current flows.
A blown bulb in a series circuit means that all the other bulbs will go out as well.
In series circuit as we remove a bulb then all the bulbs would go off But in parallel as we remove one bulb other bulbs would glow even brighter
If the switch is in the same series circuit as the bulb and the filament of the bulb is not broken then the bulb should light.
Nothing. That's why it's a parallel circuit. If it was a series circuit, then the first bulb would go out.
The circuit is open and no current will flow. All other lights in series will go out.
The circuit will have the flow of electricity interrupted.
I assume you re asking that if a bulb in series circuit burns out, then what happens to the other bulbs. If a bulb in a series circuit burns out, other bulb do not light, since the circuit s broken.
Unscrewing any bulb in a series circuit turns them all off. This is the same as opening the switch that controls them.
The other light bulb still continues to shine if one light bulb is taken out of a parallel circuit. In a series circuit if one light bulb is removed the other light bulb goes black. This happens because the circuit is incomplete.
The 2 bulb series circuit , a 3 bulb series circuit will increase resistance and therefore reduce the voltage across the bulb. The current in all points of the circuit will remain the same according to Kirchhoff.
The other bulb will no longer be lit because the circuit will be incomplete.