How many moles of nitrogen atoms are present in 53.55 g of FeNO32?
Molar mass of Fe(NO3)2 is 55.85 + 2(14.00 + 3(16.00)) = 179.85
g/mol Therefore, number of moles of Fe(NO3)2 present is
53.55/179.85 = 0.2977 mol For each molecule of Fe(NO3)2, there are
two atoms of nitrogen associated with it. Therefore, there are
0.2977*2 = 0.5954 mol of nitrogen atoms