Yes, if the iron ion is iron(II), which means it has a charge of 2+. FeS is called iron(II) sulfide. If the iron ion is iron(III), with a charge of 3+, then the formula unit would be Fe2S3, and would be called iron(III) sulfide.
That is not a question.
FeS + 2HCl => H2S + FeCl2
Yes, that is correct other than that it would need to add a few things:
2Fe(s) + 6HCl(aq) ==> 2(FeCl3)(s) + 3H(g)
FeO + 2H+ + [Cl-] --> Fe2+ + H2O + [Cl-]
Note: Cl- can be excluded from reaction eq., it doesn't take part in it, it is called: [tribuned]
Almost. FeS + 2 HCl = FeCl2 + H2S
FeS + 2HCl = FeCl2 + H2S
FeS + 2HCl --> Fe2+ + H2S + 2 Cl-
Yes?
Single Displacement
Displacement reaction , as HCl displaces S of FeS to give H2S
The reaction of Fe2O3 and H2S produces FeS, sulfur and water. The complete chemical reaction is Fe2O3 + H2S = 2 FeS + S + 3 H2O.
Iron(II) sulfide plus hydrochloric acid produces iron(II) chloride plus hydrogen sulfide. * H2S is normally just called hydrogen sulfide. FeS + 2HCl --> FeCl2 + H2S
When CS2 is added to reaction mixture Fe + S = FeS , it would dissolve the excess 'S' leaving the solids Fe and FeS without any change.
Single Displacement
Displacement reaction , as HCl displaces S of FeS to give H2S
The reaction of Fe2O3 and H2S produces FeS, sulfur and water. The complete chemical reaction is Fe2O3 + H2S = 2 FeS + S + 3 H2O.
Iron(II) sulfide plus hydrochloric acid produces iron(II) chloride plus hydrogen sulfide. * H2S is normally just called hydrogen sulfide. FeS + 2HCl --> FeCl2 + H2S
FeS+2HCl-->FeCl2+H2S Moles of H2S produced equal to moles of FeS used. Moles of H2S=12\34=0.353mol Grams of Fes=0.353*88=31.05g
water [H20]
FeS + 2H+ -> Fe2+ + H2S
Zn(s) + 2HCl(aq) ---> ZnCl2(aq) + H2(gas)
CaO+2H2CL2O
CaO+2H2CL2O
FeS + 2HCl >> FeCl2 + H2S 75 grams FeS (1mole FeS/87.92 grams)(2 mole HCl/1 mole FeS) = 1.71 moles HCl 2 Molar HCl = 1.71 moles HCl/Liters = 0.855 Liters HCl, or as asked for; 855 milliliters of hydrochloric acid needed
CuO + 2HCL - CuCl2 + H2O