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Isochoric process is a process in which change in pressure and temperature takes place in such a way that the volume of the system remains constant.
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What is isochoric?
Isochoric process is a process in which change in pressure and temperature takes place in such a way that the volume of the system remains constant.
If 800 joules of heat are added to a gas in an isochoric process what is the change in its internal energy?
The change would be 100 joules, because an isochoric system can not perform the work.
Why does work done is zero in isochoric process?
work done (by) the system equals zero , W=P(v2 - v1)= zero , where v2 = v1
What is the difference between isobaric and isochoric process?
An isobaric process is a thermodynamic-processin which the pressure stays constant: Δp = 0 The term derives from the Greek isos, meaning "equal," and barus, "heavy." The heat transferred to the system does work but also changes the internal energy of the system:
What is true about an isochoric process?
Temperature is constant.ΔU = 0 W=Q
List four sources of thermal energy?
Solar Wind nuclear heat (Fossil fuel)
What is the difference between otto cycle and diesel cycle?
the difference is the heat addition type In Otto Cycle the heat addition is Isochoric ((constant volume)) In Diesel Cycle the heat addition is Isobaric ((constant pressure))
Does energy increase or decrease when gas becomes a liquid?
Energy content of the molecules of gas decreases. Energy of the system remains same. But it depends on what the conditions are too. Depends on the process of conversion: If it's isobaric, then decreases If it's isochoric, then decreases If it's isothermal, then increases If it's adiabatic, then no change
Why work done is zero in isochoric process?
Because the volume of the gas remains constant. U= Q+W W=P⌂V ⌂V=0 so,W=0 Suppose you have a close spray can.The volume of gas within it is constant but you throw it in the fire,the volume remains the same although the temperature and internal energy as well as the pressure changes but since volume remains the same so work done is zero.
Why has a gas two values of molar heat capacities?
Gasses have two specific heat capacities because the boundary conditions can affect the number by up to 60%. Therefore, a number is given to each boundary condition: isobaric (constant pressure) or isochoric (constant volume). In an ideal gas, they differ by the quantity R (the gas constant - the same one you use in the ideal gas law): Cp = Cv + R where Cp is the isobaric molar heat capacity (specific heat) and Cv is the isochoric molar heat capacity.
Give examples of the first law of thermodynamics in which no work is done on the system?
Work can be calculated as an integral of PdV, so if volume doesn't change (dV = 0) there is no work. Changing the temperature of an isochoric system involves no work on or by the system - unless you are moving the system around like lifting it or lowering it or shoving it or decellerating it.
Work done is not a state function?
In mechanics,work done(work=force.displacement of body) by a body is independent of path.It only depends on the initial and final state of the body.However in thermodynamics,the work done by an ideal gas(work=pressure.change in volume of gas) depends on the path taken(isochoric,isothermal,isobaric,adiabatic)
