N2 / N3 qualification is a trade theory (Electrician, Motor mechanic, Plumber, Mechanotechnologist, Geologist and related career) qualification before you do your Apprentice. I South Africa, before you are admitted for and apprentice service Training) you need to have a N3 qualification.
The shorter the wave length the more energy. The further the electron falls, the more energy that will be emitted and the shorter the wavelength.
The chemical formula for a nitride ion is N-3.
Ne (neon) completes n3.
N1*V1 = N2*V2 (where N1 & N2 are the normality of respective acid or base while V1 & V2 is their respective volume).
The balanced equation for the reaction of NH3 (g) with NO (g) is the following 2NH3 (g) + 3NO (g) ---> 2.5N2 (g) + 3H2O (l). Since at constant temperature and pressure, moles of gas (n) and volume of gas (L) are proportional. n1 / V1 = n2 / V2 so V2 = n2 * V1 / n1 where n2 = 2, n1 = 3, and V1 = 30.0 L. This means that V2, or the volume of NH3 (g) needed is 20.0 L.
class Program { static void Main(string[] args) { int n1, n2, n3,i; n1 = 0; n2 = 1; for (i = 1; i <= 20; i++) { n3 = n1 + n2; if (n3 <= 200) { Console.WriteLine(n3); n1 = n2; n2 = n3; } } Console.ReadKey(); } }
declare n1 number; n2 number; n3 number; begin n1:=3 n2 :=5 n3:= sum(n1,n2); dbms_output.put_line( n3); end
Input N1, N2, N3 Max = N1 If N2 > Max then Max = N2 If N3 > Max then Max = N3 Display Max
n1=val(text1.text) n2=val(text2.text) n3=val(text3.text) text4.text=(n1*n2*n3)/100
Nrem (n1, n2, n3)
n1= 25 n2= n1+1 n3= n1-1 n4=n1+2 n5=n1-2
The following is a schematic program. Details will depend on the language.n1 = 1output n1n2 = 1output n2.start loopn3 = n1 + n2output n3got enough numbers?if yes go to end elsen1
P(x=n1,y=n2) = (n!/n1!*n2!*(n-n1-n2)) * p1^n1*p2^n2*(1-p1-p2) where n1,n2=0,1,2,....n n1+n2<=n
#include<stdio.h> int main(){ int n1,n2; printf("\nEnter two numbers:"); scanf("%d %d",&n1,&n2); while(n1!=n2){ if(n1>=n2) n1=n1-n2; else n2=n2-n1; } printf("\nGCD=%d",n1); return 0; }
It is a three-way case statement. ( Arithmetic IF statement) IF(exp) n1,n2,n3 meaning go to n1 if expr < 0 ( value is negative) go to n2 if expr = 0 ( value is zero) go to n3 if expr > 0 ( value is positive) IF(expr1-expr2) n1,n2,n3 meaning go to n1 if expr < expr2 go to n2 if expr = expr2 go to n3 if expr > expr2 reference: Fortran 77 with 90 Applications for scientific and engineers second edition RAMA N. REDDY CAROLA A. ZEIGLER
As there is only one number 288818. Average = (n1 + n2 +n3 ....... nx)/x = (28818)/1 = 28818
#include<stdio.h> int main(){ int n1,n2; printf("\nEnter two numbers:"); scanf("%d %d",&n1,&n2); while(n1!=n2){ if(n1>=n2-1) n1=n1-n2; else n2=n2-n1; } printf("\nGCD=%d",n1); return 0; }