575 and 757 both qualify.
575, 757
A palindrome reads the same forward and in reverse. This tells me that at leastthe first digit and the last digit must be the same. So it's not possible to have a6-digit palindrome "with no same digits".The largest 6-digit palindrome, with just enough repetition of digits to make it apalindrome and no more, would be 987,789 .
25 can be either the product of 1 and 25, or the product of 5 and 5. Since there are two digits in the number, the answer can only be 55. This makes sense, since 55 is divisible by 5, and the product of 5 and 5 is 25.
There are five such numbers: 11, 12, 15, 24 and 36.
I am a 3 digit number divisible by 7 but not 2 the sum of my digits is 4 what number am I
You cannot because there are no duplicate digits.
12 or 24
55.
12
A palindrome reads the same forward and in reverse. This tells me that at leastthe first digit and the last digit must be the same. So it's not possible to have a6-digit palindrome "with no same digits".The largest 6-digit palindrome, with just enough repetition of digits to make it apalindrome and no more, would be 987,789 .
Of the ten digits, 0 is the only one that is divisible by 9.
252
25 can be either the product of 1 and 25, or the product of 5 and 5. Since there are two digits in the number, the answer can only be 55. This makes sense, since 55 is divisible by 5, and the product of 5 and 5 is 25.
040
There are three such numbers: 12, 24 and 36.
Every palindrome with an even number of digits is divisible by 11. The easiest way to see this is to recall the divisibility rule by 11: if a number X is written as ABCDEFG... (here A,B,C, ... are digits), then it's divisible by 11 if and only if the sum A-B+C-D+E-F+G-... is divisible by 11. In a palindrome with an even number of digits, each digit will appear in an odd position and in an even position, so when we calculate this sum, it will be added once and subtracted once, canceling. Since all the digits cancel, the sum A-B+C-D+... will be 0, which is divisible by 11. So the original number ABCD....DCBA was also divisible by 11.
12 and 2412 and 2412 and 2412 and 24
There are several. 12. Divisible by 3 and 2. 24 divisible by 8 and 6. 36 divisible by 18 and 9. There may be more LCKMA