# What is a Mk 113 MOD 0?

No such nomenclature. You're probably thinking of the Mk 13 Mod 0, which is a 40mm grenade launcher designed by Fabrique Nationale for use with the FN SCAR. The launcher itself is marketed as the GL1, and was designed for use with the FN-2000. Mk 13 Mod 0 is a USSOCOM nomenclature for a variant of the GL1, designed for use with the FN SCAR.

### How many atomic bombs were made for World War 2?

Four were completed prior to Japan's surrender: MK-III, Gadget; tested at Trinity site in NM MK-I, Little Boy; dropped by the B-29 Enola Gay on Hiroshima MK-III, Fat Man; dropped by the B-29 Bockscar on Nagasaki MK-III, unnamed; arrived in San Francisco on August 18, returned to Los Alamos The US had production plans to make 20 more in 1945 if Japan had refused to surrender: 3 MK-III in September 3 MK-III in October 7…

### What number containing the numbers 1 through 9 with all numbers only used once is divisible by all the numbers from 1 through 9?

36288 WRONG! (1*2*3*4*5*6*7*8*9)/10 WRONG! I obviously misreads the question. after writing a simple visual basic program, see below. I am changing my answer to "does not exist." as the program failed to return a value. Private Sub Command0_Click() Dim i As Long i = 1 Do While i Mod 9 > 0 Or i Mod 10 = 0 i = i + 1 Do While i Mod 8 > 0 Or i Mod 10 =…

### What is the lowest common multiple for 2 3 and 9?

We see that we must find a number n such that it satisfies the condition: n ≡ 0 (mod 2) ≡ 0 (mod 3) ≡ 0 (mod 9) Since 9 is a multiple of 3, we can forget about the 0 (mod 3). Since 2 and 9 are relatively prime, the Chinese Remainder Theorem states that there indeed exists a number n such that it satisfies n ≡ 0 (mod 2) ≡ 0 (mod 9)…

### Why derivative of mod x does not exist graphically?

Because mod(x) is not "smooth at x = 0. Suppose f(x) = mod(x). Then f'(x), if it existed, would be the limit, as dx tends to 0, of [f(x+dx) - f(x)]/dx = limit, as dx tends to o , of [mod(x+dx) - mod(x)]/dx When x = 0, this simplifies to mod(dx)/dx If dx > 0 then f'(x) = -1 and if dx < 0 then f'(x) = +1 Consequently f'(0) does not exist and hence…

### What was the atomic bomb that was dropped on Japan?

MK-1, Little Boy, Uranium Gun Bomb, Hiroshima, August 6, 1945 MK-3, Fatman, Plutonium Implosion Bomb, Nagasaki, August 9. 1945 MK-3, unnamed, Plutonium Implosion Bomb, not delivered because Japan had already surrendered on August 14, 1945, was ready in San Francisco, CA on August 18, 1945 to be ferried by Colonel Paul Tibbets to Tinian for delivery to Japan. Bomb was returned to Los Alamos. The U.S. had a production schedule that would have allowed 20…

### Why does 1 plus 1 equals 0 in binary?

1 + 1 = 0 in binary. Why does this happen? Note: Adding binary numbers is related to modulo 2 arithmetic. Let's review mod and modular arithmetic with addition. modulus 2 is the mathematical term that is the remainder from the quotient of any term and 2. For instance, if we have 3 mod 2, then we have 3 / 2 = 1 + ½. The remainder is 1. So 3 ≡ 1 mod 2…

### Can you find a square number that when divided by 3 has a remainder of 2?

No because it is impossible. Let mod(x.3) denote the remainder when x is divided by 3. Let n be any integer. Then mod(n,3) = 0,1 or 2. When mod(n,3) = 0, mod(n2,3) = 0 When mod(n,3) = 1, mod(n2,3) = 1 When mod(n,3) = 2, mod(n2,3) = 4 and, equivalently mod(n2,3) = 1. So, there are no integers whose squar leaves a remainder of 2 when divided by 3.

### Who built the first hydrogen bomb?

US, 1952 Ivy Mike cryogenic liquid deuterium/tritium test device. The device itself, nicknamed "Sausage", measured 80 inches (2.03 m) in diameter and 244 inches (6.19 m) in height and weighed about 54 tons, its outer steel wall was 10 to 12 inches thick. It contained a triple thermos bottle holding the liquid fuel and a liquid hydrogen circulation system to keep the fuel cold. The device and all its tons of support equipment were on…

### What is the Strongest Rifle in the World?

Actually,there is a "strongest rifle", these are the SCAR .It is manufactured in two main versions; Light (SCAR-L, Mk 16 Mod 0)and Heavy (SCAR-H, Mk 17 Mod 0). The L version fires 5.56x45mm NATO using improved STANAG (M16) magazines. The H fires the more powerful 7.62x51mm NATO from a newly designed 20-round magazine. Different length barrels will be available for close quarters battle and for longer-range engagements. The initial solicitation indicated that the SCAR-H would…

### PROVE THAT nnn-n is divisible by 6?

A number is divisible by 6 if it is divisible by 2 and 3. Look at 333-3 which is 330 The sum of the digits is 6 and it is even so it is divisible by 6 Now consider 222-2 which I picked because unlike 333, 222 has even digits. 222-2=220, one again even number so divisible by 2 but NOT divisible by 3 so NOT divisible by 6 So it look like this is…

### Gauss Problem 4 A positive integer n is such that number 2n plus 1 and 3n plus 1 are perfect squares. Prove that n is divisible by 8?

This proof uses modular arithmetic. If you are unfamiliar with this, the basic principle is that if we have integers a, b, and a nonzero integer c, then a = b (mod c) if a/c and b/c have the same remainder. For example, 8 = 2 (mod 3), because 8/3 and 2/3 have remainder 2. One property of this relation is that for any integer x and for any nonzero integer y, there exists a…

### Who makes m21ebr sniper rifle?

The M21 and Mk 14 EBR is a variation of the M14 rifle, which was manufactured by Springfield Armory, Harrington & Richardson Arms Corp, Olin Mathieson Chemical Corp, and Thompson-Ramo-Wooldridge Inc. That's where the receiver and internals for the Mk 14 Mod 0 EBR come from. Enhanced modifications come from Smith Enterprises Inc. The weapon itself is actually assembled from these components by a department of the US Navy known as the Naval Surface Warfare…

### Will the number 777 be in the sequence that increase by 7 and why?

That all depends upon the first term of the sequence: As long as the first number is less than, or equal to 777 and as long as (first_number MOD 7) ≡ (777 MOD 7) will 777 be in the sequence. 777 MOD 7 ≡ 0 ⇒ if, and only if, first_number ≤ 777 and first_number MOD 7 ≡ 0 (ie 7 divides the first number) will 777 be in the sequence.