V+4 O-2 <--- these are the ions and their charges
V+2 O-1 <--- because atoms form a bond in a set ratio, we can reduce their charges and divide them by 2
V+2 O-1 O-1 <---- the charges have to add up to zero, so one +2 vanadium ion will cancel out two -1 oxygen ions
VO2 <--- simplify
Vanadium (IV) Carbonate
V4+ CO3-2
4 electrons -2electrons
V2 (CO3)4 We have to reduce it
So It is V(CO3)2
Vanadium (IV) carbonate is V(CO3)2
Vanadium carbonate has the chemical formula V(CO3)2.
The formula for vanadium(iv) sulfide is VS2.
The formula for Vanadium (IV) carbonate is V(CO3)2.
V2Se5 is the formula for vanadium V selenide.
This is vanadium carbonate.
NCO3 is the chemical formula for nitrogen carbonate.
The chemical formula of calcium carbonate is CaCO3.
The formula for Vanadium (IV) carbonate is V(CO3)2.
V2Se5 is the formula for vanadium V selenide.
This is vanadium carbonate.
PV = vanadium phosphide.
The chemical formula for iron carbonate is FeCO3.
NCO3 is the chemical formula for nitrogen carbonate.
The chemical formula of calcium carbonate is CaCO3.
VI3 is the chemical formula of vanadium iodide.
Vanadium phosphide is the chemical name for V3P3.
Silver nitrate chemical formula is: AgNO3. Sodium carbonate chemical formula is: Na2CO3.
VBr3
NiCO3 is the chemical formula for nitrogen carbonate.