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V+4 O-2 <--- these are the ions and their charges

V+2 O-1 <--- because atoms form a bond in a set ratio, we can reduce their charges and divide them by 2

V+2 O-1 O-1 <---- the charges have to add up to zero, so one +2 vanadium ion will cancel out two -1 oxygen ions

VO2 <--- simplify

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15y ago
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12y ago

Vanadium (IV) Carbonate

V4+ CO3-2

4 electrons -2electrons

V2 (CO3)4 We have to reduce it

So It is V(CO3)2

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14y ago




Vanadium (IV) carbonate is V(CO3)2

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6y ago

Vanadium carbonate has the chemical formula V(CO3)2.

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6y ago

The formula for vanadium(iv) sulfide is VS2.

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Q: What is chemical formula for vanadium carbonate?
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