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Lead iodide can be obtained as a yellow precipitate by reacting solutions oflead(II) nitrate and potassium iodide the other compound created by the reaction is potassium nitrate which is a white power but as it is soluble it does not form a precipitate.

2KI + Pb(NO3)2 --> 2KNO3 + PbI2

the balanced equation if you were needing it

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13y ago
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11y ago

Let's see.

2KI + Pb(NO3)2 --> 2KNO3 + PbI2(s)

Lead begins by being ionically bonded to the polyatomic ion nitrate while potassium is ionically bonded to iodine and nitrate sequentially, so the only possibility is the lead bonding to iodine and precipitating out of solution with the white color observed in this reaction. The precipitate is in bold.

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15y ago

It will form a solution called Lead Iodine which in turn is a precipitate.

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9y ago

Potassium iodide is the yellow solid. Chemical formula of it is PbI2. It dissolves in hot water.

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14y ago

Rough solubility rules: most nitrates are soluble, most alkali metal salts are soluble. The precipitate is therefore most likely something that is neither a nitrate nor an alkali metal salt.

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8y ago

The products are lead iodide (PbI2) insoluble in water and potassium nitrate.

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6y ago

The yellow precipitate is lead iodide, PbI2. The reaction is....PbSO4(aq) + 2KI(aq) ==> PbI2(s) + K2SO4(aq)

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Q: What is the yellow solid after the reaction between potassium iodide and lead2nitrate?
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