Lead iodide can be obtained as a yellow precipitate by reacting solutions oflead(II) nitrate and potassium iodide the other compound created by the reaction is potassium nitrate which is a white power but as it is soluble it does not form a precipitate.
2KI + Pb(NO3)2 --> 2KNO3 + PbI2
the balanced equation if you were needing it
Let's see.
2KI + Pb(NO3)2 --> 2KNO3 + PbI2(s)
Lead begins by being ionically bonded to the polyatomic ion nitrate while potassium is ionically bonded to iodine and nitrate sequentially, so the only possibility is the lead bonding to iodine and precipitating out of solution with the white color observed in this reaction. The precipitate is in bold.
It will form a solution called Lead Iodine which in turn is a precipitate.
Potassium iodide is the yellow solid. Chemical formula of it is PbI2. It dissolves in hot water.
Rough solubility rules: most nitrates are soluble, most alkali metal salts are soluble. The precipitate is therefore most likely something that is neither a nitrate nor an alkali metal salt.
The products are lead iodide (PbI2) insoluble in water and potassium nitrate.
The yellow precipitate is lead iodide, PbI2. The reaction is....PbSO4(aq) + 2KI(aq) ==> PbI2(s) + K2SO4(aq)
530,3 g potassium iodide are needed.
is it potassium iodide
The boiling point of potassium iodide is 1 330 0C. The boiling point of potassium chloride is 1 420 0C.
The only iron iodide listed in the Handbook of Chemistry and Physics (1985) is iron (II) iodide, with the formula FeI2 Hypothetically, there could be an iron (III) iodide with the formula FeI3, but this probably spontaneously transforms into iron (II) iodide and elemental iodine.
Chromium (III) Iodide
the reaction between bleach anb potassium iodide is KI+NaCl2--->KCl2+NaI
Yes, I know strontium iodate does.
potassium
learn your chemistry and find out.... Bye
The only known and possible reaction is the following redox (reduction-oxidation) reaction between I3- (Iodine-Iodide complex) and S2O32- (thiosulfate)I3- + 2 S2O32- --> 3 I- + S4O62-ox. + red.So the reaction between potassium iodide (KI) and potassium thiosulfate (K2S2O3) is NOT possible because they both are reductors (electron donors).Iodine-Iodide complex is essentially Iodine is an oxidator, bound to a non-reacting I- ion (Iodide)
No reaction.
In the reaction: Lead (Ⅱ) Nitrate + Potassium Iodide → Potassium Nitrate + Lead (Ⅱ) Iodide.. all nitrates are soluble and lead(ii)iodide is insoluble.
Bromine and Potassium iodide react to form Potassium bromide and Iodine.
Please mention this reaction.
No reaction because the anion is common in both compounds.
No, reaction
Assuming a double displacement reaction. 2KI + BaS --> K2S + BaI2