The equivalent resistance you would have to place in series with an ideal battery (which of course does not exist) of the same voltage to get the same behavior (voltage drop with load) as the real battery has. It is a mathematical modeling technique to help in circuit analysis.
BATTERY have very low resistance . you may short a battery and get virtual zero volts but lots of current therefore can be named as a current source
the internel resistense of ammeter is as maximum as possible. for ideal ammeter it is infinite
The voltage of the battery, and the resistance of the circuit (including the resistance of the wire and the internal resistance of the battery).
As it ages, its Kirchhoff virtual 'internal resistance' increases. Pictured this way, the practical effect is that the open-circuit voltage of a failing cell still measures good, but the voltage quickly sags when you try to draw any current from it
The internal battery is a battery in the game pack that stores energy to keep track of things like the passage of time when the game is not in use.
It's all relative. A battery has internal resistance. Batteries are not "ideal" voltage sources. If there is a "heavy" load on the battery (low resistance), the voltage you measure on the outside of the battery will be lower. A car battery is normally thought of as a 12 volt battery. When there is no load (disconnected) you can often measure in excess of 13 volts if it's fully charged. During normal cranking of the engine, the voltage can drop below 11 volts.
The voltmeter would read 12 volts. An ammeter connected to to battery would only read 4 amps (12 volts divided by 3 ohms =4)
No, it is desirable for a battery to have a low internal resistance.
The value of internal resistance of 1.5 volt battery is 0.5 ohms.
Yes
Internal resistance is approximately equal to 94.667
That will depend on the internal resistance of the battery. I = E / R Where I is the current, E is the open circuit battery voltage, and R is the internal resistance of the battery.
You have to imagine the internal resistance as being in parallel with any load you connect. You get the maximum possible current when the load is zero. In this case, just apply Ohm's Law. That is, divide the voltage by the internal resistance.
The voltage of the battery, and the resistance of the circuit (including the resistance of the wire and the internal resistance of the battery).
There is internal resistance in a battery because a battery is not an ideal voltage source. It may be close, but it is not ideal. As a result, analytically, there will be some series resistance, resistance which places a limit on the maximum current that the battery can provide. While no battery is ideal, most are sufficiently ideal to not require any consideration of the internal resistance. If your circuit is dependent on the internal resistance of a battery, then it is probably not well suited for that application.
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It causes the battery's voltage to drop when a current is drawn from it.
Batteries are rated as ampere/hour any circuit that draws power from it effects it. The lower the internal resistance of the circuit the shorter the useful battery life as discharged.
Battery maximum current is limited by the internal resistance of the battery. As the current is increased towards this maximum, you will notice the output voltage appear to shink towards zero. What this means is the voltage the battery is capable of supplying is being dropped almost completely across the internal resistance, so no real power is available to use.This internal resistance is dependent on the chemical and physical makeup of the battery.