What is the oxidation number of N in N2H4?

Answer 1

N has an oxidation state of -2

Since H is +1 for each atom (+1)(4atoms) =+4 total

The compound must be neutral

so N is -2 for each atom (-2)(2atoms)= -4 total

the orders the N and H are in does not affect the sign.

Answer 2

-3. H is given a +1 (this is not a metallic hydride) and the charge on the ammonium ion is +! so the sum of oxidation numbers of the elements in the ion is +1.

Answer 3

it is +2 as oxidation number = oxidation state of the element * total no. of atoms of the element

in the compound

Answer 4

2(n) + 4(-2) = 0

2n - 8 = 0

2n = 8

n= +4

Answer 5

O.S. of Nitrogen = -2

Answer 6

2

Answer 7

3