What is the percent composition by mass of C10H14O?

Answer 1

Percent composition means finding the total mass of each element in a molecule and then dividing it by the molecular mass. Use the molecular formula to help you find out how many atoms of each element you'll need.

For carbon: 6 C x 12 g = 72 g

For hydrogen: 10 H x 1 g = 10 g

For oxygen: 5 O x 16 g = 80 g

Molecular mass = C + H + O = 72 + 10 + 80 = 162 g

Percent composition of C = 72/162 = 0.4444 = about 44.45%

Percent composition of H = 10/162 = 0.061728395 = about 6.17%

Percent composition of O = 80/162 = 0.49382716 = about 49.38%

Answer 2

Furaneol has three elements in differing ratios, six carbon to eight hydrogen to three oxygen. The total mass is 128.126, with carbon making up 72.064 or 56.2 percent.

Answer 3

The percent composition by mass of C10H14O: carbon-80 % , oxygen-10,67 %, hydrogen-9,33 %.

Answer 4

• C is 80%
• H is 9.4%
• O is 10.6%

Answer 5

25%