The formula for amps when kilowatts are stated is; kW x 1000/1.73 x Volts x pf.
10 x 1000/1.73 x 415 x .8 = 10000/574 = 17 amps.
The electrical code states that motor feeders have to be rated at 125% of the motors FLA (full load amps). 17 x 125% = 21 amps.
A #10 copper conductor with an insulation factor of 75 or 90 degrees C are both rated at 30 amps.
Depending on the method of cable installation, if the cable is unenclosed you can get away with 6mm sq otherwise you need 10mm sq
100kw/415V=241Amp *1.25 = 302 Amps
NEC 310.16
wire size 350 MCM
p= V*I*COS FIEE SAY COS PYE IS UNITY10*1000=230*I*1I= 10000/230I=43.4 AComment10 kW is the output power of the machine. You will need to know the machine's efficiency in order to determine its input power before applying the above equation.
To answer this question the voltage of the unit must be given.
If the generator is a 12 lead reconnectable, you can use something called a zig-zag connection.Check the link below. It is an installation manual for a Marathon generator. Zig-zag connections are shown on page 8. For a home, you would use the low zig-zag connection for 120/240V (in the US). One caveat: you can only load a zig-zag single-phase connected generator to a maximum of 66% of its rated load. So, a 15kW 3-phase generator would only provide 10kW single-phase power. If this doesn't quite make sense, hire a pro!IF YOU ARE NOT ALREADY SURE YOU CAN DO THIS JOBSAFELY AND COMPETENTLYREFER THIS WORK TO QUALIFIED PROFESSIONALS. If you do this work yourself, always turn off the power at the breaker box/fuse panel BEFORE you attempt to do any work AND always use a meter or voltage indicatorto insure the circuit is, in fact, de-energized.
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The 3 phase formula you are looking for is I = HP x 746/1.73 x E x% Eff x pf. Where I = amps, E = voltage, %Eff = percent efficiency of the motor and pf = power factor.
To answer this question the full load amperage of the motor and what phase the motor is, should have been given. This answer uses the motor amperage give in the electrical code book and will be close for your purpose. A 6 HP is not a common size motor. 7.5 HP motor is 25.3 amps. Using a power factor of 90%. W = I x E x 1.73 x pf, W = 25.3 x 220 x 1.73 x .9 = 8666 watts. A 10kW three phase generator will probably start the motor if it is not under load when it starts. A 15 kw generator would be better. A single phase 7.5 HP motor draws 40 amps. W = I x E x pf = 40 x 220 x .9 = 7920. Again A 10kW single phase generator will probably start the motor if it is not under load when it starts. A 15 kw generator would be better.
Yes, it is generally safe to start an AC motor with an inverter that has a higher power rating. The inverter's capacity should exceed the motor's power requirements to ensure sufficient starting torque. However, it is important to ensure that the inverter is correctly configured and that the motor is compatible with the inverter's voltage and frequency output.
10kw generators are available for purchase at Home Depot. They sell the Briggs & Stratton models which are known to be durable and dependable. These generators can get you through the worst of power outages.
Since watts = volts times amps times 1.73 times power factor (for a three phase motor): W = E * I * 1.73 * PF Solving for I: I = W / (E * 1.73 * PF) Lets say your motor has a PF of 0.85: I = 10000 / (415 * 1.73 * 0.85) I = 16.39A If this is for your homework (I hope not) and PF is not given, then you will substitute 1.0 for the PF and, of course, arrive at a different answer!
The short answer is no. The long answer is no, not if you are using standard 100-120 volt or 220-240volts found in most (all?) countries The following is a simplified best case scenario, which incorrectly assumes a power factor of 1. Power = Volts * Amps Watts = Volts * AMPS (Actually VA = Volts * Amps, but VA=Watts in best case scenario) but 10kw > 240 * 32. David
10kW = 10,000 watts
p= V*I*COS FIEE SAY COS PYE IS UNITY10*1000=230*I*1I= 10000/230I=43.4 AComment10 kW is the output power of the machine. You will need to know the machine's efficiency in order to determine its input power before applying the above equation.
To answer this question the voltage of the unit must be given.
101.9m
yes
The formula you are looking for is I = W/E. Amps = Watts/Volts. As you can see a voltage must be stated to answer this question. 10kW = 10000 watts.