303
100
99 + 98 + 97 = 294
505
It is instructive to note that you can rewrite 1+2+3+4....+99+100 as 1+100+2+99+3+98....+50+51 Then you can group each pair of numbers as (1+100)+(2+99)+(3+98)+...+(50+51) All of these couplets add up to 101, and there are 50 of them. Thus the sum of the first 100 whole numbers is 50x101. This can be calculated at 5,050.
Add them up. 90, 91, 92, 93, 94, 95, 96, 98, 99, 100
100
100 + 99 + 98 + 2 + 1 + 0.3 = 300.3
5,050
Sum of numbers from 1 to 100:(1+100) + (2+99) + (3+98) + (4+97) + ... + (49+52) + (50+51) =50 pairs, each pair adds up to 101= (50 x 101)= 5,050
99 + 98 + 97 = 294
297
The median is (98+99)/2 = 98.5
505
The three consecutive numbers whose sum is 294 are 96, 98 and 100. Also, 97, 98 and 99.
IN WHOLE NUMBER FIRST DIGIT IS 0 SO THAT WE HAVE TO SUM 1-98 NUMBERS :-SUM OF 1-10 IS 55 SO IN SUM OF EACH 11-20,21-30......THE UNIT DIGIT WILL COME 5 SO FOR THAT WE MULTIPLY 5*9+1+2+3+4+5+6+7+8 AFTER THIS CALCULATION WE GOT 1 AS A UNIT DIGIT NUMBER
It is instructive to note that you can rewrite 1+2+3+4....+99+100 as 1+100+2+99+3+98....+50+51 Then you can group each pair of numbers as (1+100)+(2+99)+(3+98)+...+(50+51) All of these couplets add up to 101, and there are 50 of them. Thus the sum of the first 100 whole numbers is 50x101. This can be calculated at 5,050.
1 + 98 = 99