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The electric space heater. It's the only common machine that's 100% efficient.

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0The condition for maximum efficiency of a d.c. machine is that VARIABLE LOSSES must be equal to CONSTANT LOSSES i.e., variable losses = constant losses..

Machine closest to an ideal machine should consume with nearly 100% efficiency and deliver maximum to output... In reality there is no such machine exists... But we can say a machine is close to an ideal by checking its efficiency.

In any machine, some energy will usually be wasted. This will reduce the efficiency below the theoretical maximum of 1.0. However, please note that, if the efficiency is above 95% (or 0.95), when rounded to the nearest tenth you will get 1.0.In any machine, some energy will usually be wasted. This will reduce the efficiency below the theoretical maximum of 1.0. However, please note that, if the efficiency is above 95% (or 0.95), when rounded to the nearest tenth you will get 1.0.In any machine, some energy will usually be wasted. This will reduce the efficiency below the theoretical maximum of 1.0. However, please note that, if the efficiency is above 95% (or 0.95), when rounded to the nearest tenth you will get 1.0.In any machine, some energy will usually be wasted. This will reduce the efficiency below the theoretical maximum of 1.0. However, please note that, if the efficiency is above 95% (or 0.95), when rounded to the nearest tenth you will get 1.0.

Efficiency of any electrical machine is maximum when the load on that machine is such that the variable loss ( copper loss) is equal to constant loss (eddy current loss, hysteresis etc).the same applies to dc machines too.

What does the efficiency of a machine describe?

No heat loss = maximum output. There would be no loss of energy, which is an ideal condition.

A high efficiency machine will produce more of what is it that you want with the same power as the low efficiency one. In other words, for a low efficiency machine do as much as a high efficiency one, you have to give it more power (energy).

the efficiency is maximum in a transformer when no load loss is equal to load loss.

Mechanical Efficiency is the ratio of Actual mechanical advantage to ideal mechanical advantage.Efficiency will be maximum when Actual mechanical advantage equals that of ideal.But practically not possible.Actual mechanical advantage will be less due to friction,heat,deflection etc.avoiding these loses will increase the machine efficiency.

No. Maximum efficiency occurs when the iron and copper losses are equal.

The exact condition for maximum power to be available at the load side is the equality of the resistances of both the load and the source part of the machine

The plan was carefully orchestrated to insure success. He orchestrated every movement to get the maximum efficiency from the machine.

Because efficiency is measured in a ratio. Energy out of the machine divided by energy going into the machine equals efficiency. You can get it as a percentage, but that's about it.

No machine has 100% efficiency. Because of friction and heat loss, this is impossible.

The efficiency of a machine is usually expressed as a percentage. The ideal efficiency of a machine is 100-percent.Another AnswerThere are no units of measurement for efficiency, because you are comparing like with like: output power divided by input power.

Mathematically, efficiency = (energy output) divided by (energy input) as a percentage. As if we couldn't figure this out for ourselves, one of the laws of Thermodynamics formally tells us "You can't get more energy out than what you put in." Applying this law to the formula for efficiency, it says that the maximum possible efficiency is 100%. However, the next law of Thermodynamics says "You can't even get that much out."

Because that is the obvious point to have maximum efficiency occur.

Condition for maximum efficiency is when copper loss is equal to iron loss.

The efficiency of a machine is found by dividing the amount of work done by a machine by the amount of energy used by a machine. The answer is then multiplied by 100 to give a percentage.

"High efficiency" means that a large percentage of the energy used by the machine is converted into the desired output.

It is maximum at about 75% to 100% of the motor rated load. Efficiency is maximum at unity power factor , when R=X and when variable losses Is equal to constant losses at rated load.

It is not designed that way. It is inherent characteristic of the equipment. It is true even for motors. Condition for maximum efficiency is when copper losses are equal to iron losses. In other words, efficiency is maximum when no load losses are equal to load losses. Efficiency will not be maximum at maximum load.

It is the ratio of output power given by the machine to input power supplied to the machine. i.e. Efficiency = output power of the machine / input power suplied to machine.

High-efficiency machines do more for less and are therefore more desirable than a low-efficiency machine.AnswerHigher efficiency means lower energy losses and, therefore, such machines are more economical than low-efficiency machines.

(Work out / work in) * 100 = % efficiency

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