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A.B = 7*7 + 7*3 = 49 + 21 = 70

|A| = sqrt(72 + 72) = sqrt(98)

|B| = sqrt(72 + 32) = sqrt(58)

So cos(q) = A.B/(|A|*|B|) = 0.92848

q = cos-1(0.92848) = 0.38 radians (=21.8 degrees).

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10y ago
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Q: What is the angle θ between vectors A and B if A 7ı 7ȷ and B 7ı3ȷ?
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