what isthe answer of a rhombus whose side is 16.2 cm?
130 is the area.
Let the other diagonal be x If: 0.5*12*x = 30 then x = 60/12 => x = 5 The rhombus has four interior right angle triangles with lengths of 6 cm and 2.5 cm Using Pythagoras each equal sides of the rhombus works out as 6.5 cm Perimeter: 4*6.5 = 26 cm
A triangle with side a: 7, side b: 7, and side c: 7 cm has an area of 21.22 square cm.
16 cm*16 cm =256 cm2
Length of side = sqrt(2304) = 48 cm
Find the area of a rhombus whose side is 6 cm and whose altitude is 4 cm? . Area = base * height Altitude = height. Altitude = 4 cm . A rhombus has all 4 sides equal, so the base = 6 cm . Area = base * height . Area = ____sq. cm.
130 is the area.
the diagonals of a rhombus measure 16 cm and 30 cm.find its perimeter.
14*8 = 112 sq cm
always
Since the diagonals of a rhombus are perpendicular and bisect each other, then we can use the Pythagorean theorem to find the length of the side of the rhombus. So in the right triangle, whose length of the legs are 6 and 8 centimeters, the hypotenuse length (the length of the side of the rhombus) is √(62 + 82) = √(36 + 64) = √100 = 10 cm.
140 cm
Perimeter of rhombus = 4*side = 9.6 cm
P = 140 cm
Let the other diagonal be x If: 0.5*12*x = 30 then x = 60/12 => x = 5 The rhombus has four interior right angle triangles with lengths of 6 cm and 2.5 cm Using Pythagoras each equal sides of the rhombus works out as 6.5 cm Perimeter: 4*6.5 = 26 cm
The diagonals will cross each other half way at right angles.
Base = Area/Height = 7886.2/95.7 = 82.405 cm (to 3 dp)