10111 = 16+4+2+1 = 23
111 = 4+2+1 = 7
so 23 x 7 = 161
which is 128+32+1 = 10100001
Binary: 111 + 111 = 1110 Decimal: 7 + 7 = 14
111
The number represented in base 2 by the digits 111 is equal to the decimal number 7.
12321
111 The three ones represent (4)+(2)+(1).
Binary: 111 + 111 = 1110 Decimal: 7 + 7 = 14
1110-111 in binary = 999
111 + 111 = 1110
The number 111 in binary would be 1101111
The number 7 - written in binary is... 111
111
7 in Binary is 111
Assuming that is binary: 1111112 = 63
111 = 1101111
7 = 111
111
This depends upon what "base" you are referring. In "base 10", 111 is 1101111.In "base 8", 111 is 1001001In "base 16", 111 is 100010001.Of course, if you are just asking "what is the value of 111 in base 10" that would be 7. (4 + 2 + 1)