It is a straight line equation that needs to be rearranged into slope-intercept form as folows:- 7x+2y = 5 Subtract 7x from both sides: 2y = -7x+5 Divide all terms by 2: y = -3.5x+2.5 which is now in slop-intercept form

Double first equation: 10x + 2y = 10Subtract second equation: 7x = 7x = 1, y = 0

7x-2y=10 -2y=10-7x y=-5+(7/2)x y=(7/2)x-5 (Final answer)

the answer to this problem is -2x^2y^2

3y - 3 = 2y + 5 3y - 2y = 5 + 3 y = 8

5x - 3y -7x + 2y +3x = (5-7+3)x + (-3+2)y = x - y

7x = 5+5x 7x-5x = 5 2x = 5 x = 2.5

-7x + 5 = -9 -7x = -14 7x = 14 x = 2

It's an expression in 'x' and 'y'.It may be simplified (cleaned up) to yield:7x + 2y - 2x + 3y =5x +5yor5 (x + y)

7x is still the slope, no matter what x equals.

Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution.

23 = 7x + 7x - 5 = 14x - 5 14x = 23 + 5 = 28 x = 28/14 = 2

4x - 7 = 5 + 7x x = -4

4x+5=7x-8 the ansewr is 3.25

7x-4x+2x+5=2x+14 5x+5=2x+14 3x=9 x=3

3x+2y-5=0 3x+2y=5 Im lost im only 12 work out the rest hope i helped

-2x=2y+5 +2x -2y -2y=2x+5 /-2 y=-1/1+2.5

10x + 5 which is also equal to 5(2x + 1)

7x - 9 = 3x + 5 7x - 3x - 9 = 5 7x - 3x = 5 + 9 4x = 14 x = 14/4

7x+5-14 = 28 7x = 28+14-5 7x = 37 x = 37/7 = 5.'285714' recurring

7x + 5y 7(3) + 5(2) 21 + 10 = 31

7x-1=2x+5 7x-2x=5+1 5x=6 x=6/5=1.2

7x + 5 = 68 subtract 5 from both sides 7x = 63 divide both sides by 7 x = 9

7x+10=31x so 10=31x-7x or 10 =24x in which case x=10/24 or 5/12

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