One can use integration by parts to solve this. The answer is (x-1)e^x.

int(e 3x) = (1/3)e 3x ========

Powers of e are simple to integrate. The derivative of eu equals u'eu; inversely, the antiderivative of eu equals eu/u'. Therefore, the antiderivative of e1/-x equals (e1/-x)/{d/dx[1/-x]}. The derivative of 1/-x, which can also be expressed as x-1, equals (-1)x(-1-1) = -x-2 = -1/x2.

The antiderivative, or indefinite integral, of ex, is ex + C.

The second letter is "e".

1/ln(x)*e^(1/x) if you differentiate e^(1/x), you will get ln(x)*e^(1/x). times this by 1/ln(x) and you get you original equation. Peace

The antiderivative of 1/x is ln(x) + C. That is, to the natural (base-e) logarithm, you can add any constant, and still have an antiderivative. For example, ln(x) + 5. These are the only antiderivatives; there are no different functions that have the same derivatives. This is valid, in general, for all antiderivatives: if you have one antiderivative of a function, all other antiderivatives are obtained by adding a constant.

e raised to the 0 power is 1

epi = 23.140692632779. pie = 22.459157718361. Thus, epi is greater.

E was born and raised in Union,Kentucky

Euler's constant, e, has some basic rules when used in conjunction with logs. e raised to x?æln(y),?æby rule is equal to (e raised to ln(y) raised to x). e raised to ln (y) is equal to just y. Thus it becomes equal to y when x = 1 or 0.

E major has a higher, raised third.

E. Duckett has written: 'Death and life in the tenth century'

(e^x)^8 can be written as e^(8*x), so the integral of e^(8*x) = (e^(8*x))/8 or e8x/ 8, then of course you have to add a constant, C.

e=mc2 multiplide by pie to the tenth degree of the sixth square

Well the number e, raised to 6 (e^6) is just a number (a constant), so you integrate a constant times dx gives you that constant times x + C --> x*e^6 + C

The first derivative of e to the x power is e to the power of x.

It is possible.

From harpic04 Will illiterate do ?

The tenth Governor of Maine was Samuel E. Smith, who served in the role between January 5, 1831 and January 1, 1834.

d/dx e3x = 3e3x

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