Math and Arithmetic

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Top Answer

24 x 17 = 408

so, 408 yards squared :p

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0The width is 34/17 = 2 yards

It is: 3.5 yards Check: 3.5*17 = 59.5 square yards

24*17 = 408 square yards

Area = 17*8 = 136 square units

187 sq. inches (area for a rectangle= length x width

9 meters x 17 meters = 153 square meters.

Area = 0.5*13*17 = 110.5 square yards

Diagonal = 17 cm and height = 8 cm so Length = sqrt[172 - 82] = sqrt(225) = 15 cm Then area = length*height = 15*8 = 120 cm2

Let the width be (x-3) and the length be x: width*length = area (x-3)*x = 340 square inches x2-3x-340 = 0 Solving the above quadratic equation works out as: x = -17 or x = 20 it must be the latter because dimensions can't be negative. Therefore: length = 20 inches and width = 17 inches Check: 20*17 = 340 square inches

If the area is 221 square units and the width is 17 units then the length will be 13 units because 17*13 = 221 square units.

Letting x be the length of the rectangle and (x - 8) be the width of the rectangle,x(x - 8) = 153,subtracting 153 from each side, x2 - 8x - 153 = 0,solving for x, (x - 17)(x + 9) = 0, then x = 17 or x = -9,substituting 17 for x, the dimensions of the rectangle are 17cm and 9cm.

It depends on whether the side length of 3 is the smaller or the larger of the two sides of the second rectangle. that is, is the 3 related to the 8 or the 17.

how do you find the area of a rectangle witha perimeter of 36 in You don't. You need more information For example a 1 x 17 rectangle has a perimeter of 36 and its area is 17. But a 2 x 16 rectangle also has a perimeter of 36 and its area is 32.

there is no " weight " on a rectangle. if you mean WIDTH: Keeping in mind that the formula to find an Area of a Rectangle as follow: A= LW ,where A: Area in Square Units, L:Length , W: Width Answer: W=A/L yes their is a "weight" to a rectangle. The formula is W=V(volume)xWD(weight density)

Square inches is a measure of area. This appears to be the area of a rectangle, in which case area = length x width. Area = 57in x 17in = 969in2.

A rectangle is a two dimensional figure. The question gives two dimensions (width and height) - you can't ask for a third dimension of 'length' because two are the limit.If you are looking for the length of the perimeter of this rectangle, it is 58.

228 inches, what you do is add, 97+97+17+17

Area = Length*Width so Width = Area/Length = 255/17 ft = 15 feet.

Length x width x depth/27=cubic yards Tri axel dump truck holds around 16 to 17 cubic yards of earth material.

The area for a four sided shape is length * width = area.We have the area at 17. We know that length = width. We designated length and width as x. Our new equation isx * x = 17, or x2 = 17.Now we have to isolate x.x = sqrt(17).Solving for x, we get x = 4.123.

It is 2*(50 + 17) = 2*67 = 134 inches.

Rephrase your question, because none of us have any idea what problem 17 is. For now, the area is 42.

It is: 22*17 = 374 square cm

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