The atomicity of KClO3 is one, which means that in one molecule of KClO3, there is one atom each of potassium (K), chlorine (Cl), and oxygen (O).
The percent of oxygen in KClO3 is 48.4%. This can be calculated by dividing the molar mass of oxygen in KClO3 (48 g/mol) by the molar mass of KClO3 (122.55 g/mol) and multiplying by 100%.
The atomicity of oxygen in ozone is 3. This means that each molecule of ozone contains three oxygen atoms.
2 grams of Oxygen can be obtained from 5 grams of KClO3 (only if the "CL" means "Cl", which is Chlorine! Remember that only the first letter of the atomic symbol is capitalized.)
2 KClO3 ------ 2KCl + 3O2 so 2 moles of KClO3 produces two mole of KCl. Therefore 0.440 moles of potassium chlorate will produce 0.44 moles of KCl - potassium chloride.
The oxidation number of Cl in KClO3 is +5. This is determined by assigning -2 to O and +1 to K, and then setting up an equation to find Cl's oxidation number based on the overall charge of KClO3.
the atomicity of ozone is 3 hehehehe./////////////......................
The formula for potassium chlorate is KClO3.
The atomicity of neon is 1, meaning it exists as individual atoms. Phosphorus can exist in several allotropes with different atomicities: white phosphorus has an atomicity of 4, red phosphorus has an atomicity of 1, and black phosphorus has an atomicity of 1.
The percent of oxygen in KClO3 is 48.4%. This can be calculated by dividing the molar mass of oxygen in KClO3 (48 g/mol) by the molar mass of KClO3 (122.55 g/mol) and multiplying by 100%.
The atomicity of oxygen in ozone is 3. This means that each molecule of ozone contains three oxygen atoms.
The formula (not symbol) is KClO3
To find the atomicity of an ideal gas you can use γ = Cp/Cv.
Hydrogen has an atomicity of 1, meaning that its molecules consist of single hydrogen atoms.
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atomicity in chemstry atomicity is defined as the total number of atoms present in one molecule of substance
Atomicity ? Well one definition is the same as valency which for rubidium is 1.