What is the balanced equation for Ch3COOH alone
This is the chemical formula of acetic acid not an equation.
CH3COOH + NH3 (yields) CH3COO- + NH4+
2 CH3COOH + Mg = (CH3COO)2Mg + H2
CO(g) + 2H2(g) ---> CH3OH
CaCO3 + 2 CH3COOH ------------- Ca(CH3COO)2 + H2O + CO2
KI + CH3COOH --> HI + CH3COO-K+ ROOH + 2HI --> ROH + H2O + I2 TITRATION WITH SODIUM THIOSULPHATE TO DERIVE THE PEROXIDE VALUE 2NA2S2O3 + I2 (PURPLE) --> NA2S4O6 + NaI (COLOURLESS)
One example would be: acetic acid and ammonia form ammonium acetate. CH3COOH + NH3 --------> CH3COONH4
CH3CH2OOCCH3 + H2O ===> CH3CH2OH + CH3COOH
Ch3coo(-) + h2o ---> ch3cooh + oh(-)
CH3COOH + NaHCO3 ---> CH3COONa + H2O + CO2
CH3COOH+NaHCO3 -> H2O+NaOCOCH3+CO2
CH3COOH + NaHCO3 = CH3COO-Na+ + H2O + CO2
CaCO3 + 2 CH3COOH ------------- Ca(CH3COO)2 + H2O + CO2
CH3COOH + KOH = CH3COOK + H2O
NaHCO3 + CH3COOH-------------CH3COONa + CO2 + H2O
CaCO3 + 2 CH3COOH ------------- Ca(CH3COO)2 + H2O + CO2
2K2Cr2O7 + 2H2SO4 + 3C2H5OH ---> 2Cr2(SO4)3 + 2K2SO4 + 3CH3COOH + 11H2O.
The equation for this reaction is: CH3COOH + CH3CH2OH ------> CH3COOCH3 + H2O
The reaction is: (CH3CO)2O + H2O = 2 CH3COOH
CH3COOH+NH4OH turns into H2O+CH3COONH4 have fun with chem
CH3COOH + NaOH --> CH3COONa + H2OOr better the ionic equation in water:CH3COOH + OH- --> CH3COO- + H2O[Na+ ions are left out of the equation because they don't take part in this reaction: it stays unchanged in solution]