2HC2H3O2 + Sr(OH)2 ===> Sr(C2H3O2)2 + 2H2O
Sr(s)+2H20(l)--->Sr(OH)2(aq) + H2(g)
SrO + H2O => Sr(OH)2
Sr(s) + 2HCl(aq) --> SrCl2(aq) + H2(g)
Sr + 2H2O --> Sr(OH)2 + H2
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2Na + 2H2O -> 2NaOH + H2
Strontium reacts with water producing strontium hydroxide and hydrogen gas. This is a chemical change.
Sr + 2 H2O --> Sr(OH)2 + H2 Strontium + Water --> Strontium Hydroxide + Hydrogen Gas.
Strontium hydroxide is Sr(OH)2, with a molar mass of 121.6g/mol. If you have 5.18g of it, you have 5.18/121.6=0.0426mol of it. Multiply this by Avogadro's number to get 2.56x1022 representative particles of strontium hydroxide. Assuming you mean hydroxide ions instead of hydrogen ions, it's 2 hydroxide ions per formula unit, so double it to get 5.12x1022 hydroxide ions.
Lithium + water = lithium hydroxide + hydrogen Sodium + water = Sodium hydroxide + hydrogen Potassium + water = Potassium hydroxide + hydrogen
Sodium hydroxide does not react with hydrogen gas.
3carbon-hydrogenn 2carbon-hydrogenn 16carbon-oxygen
2Na + 2H2O -> 2NaOH + H2
2Na + 2H2O = 2NaOH + H2
There isn't one because there is no reaction beyond the catalysis of the decomposition of the peroxide.
Sodium reacts with water to form sodium hydroxide and hydrogen. The balanced equation is 2Na + 2H2O --> 2NaOH + H2.
Strontium reacts with water producing strontium hydroxide and hydrogen gas. This is a chemical change.
Sr + 2 H2O --> Sr(OH)2 + H2 Strontium + Water --> Strontium Hydroxide + Hydrogen Gas.
H2+SO4-2 + 2Na+OH- >>> Na2SO4 + 2 H2O
Strontium hydroxide is Sr(OH)2, with a molar mass of 121.6g/mol. If you have 5.18g of it, you have 5.18/121.6=0.0426mol of it. Multiply this by Avogadro's number to get 2.56x1022 representative particles of strontium hydroxide. Assuming you mean hydroxide ions instead of hydrogen ions, it's 2 hydroxide ions per formula unit, so double it to get 5.12x1022 hydroxide ions.
Yes, the water and sodium produce sodium hydroxide and hydrogen!
2Na(s) + 2H2O(l) ---> 2NaOH (aq) + H2(g)