The reactants are C4H10 and O2 and the products are CO2 and H2O.
The balanced equation is as follows:
2C4H10 + 13O2 -> 8CO2 + 10H2O
In order to obtain complete combustion, there needs to be a plentiful supply of oxygen.
There are two possible reactions involving the combustion of butane, depending on whether it is complete or incomplete combustion.
Complete: C4H10 + 6.502 -> 4C02 + 5H20
Incomplete: C4H10 + 4.502 -> 4C0 + 5H20
C4H8 + 6O2 ---> 4CO2 + 4H2O
4C --> 4C
8H --> 8H : (4*2)
12O -->12O : (6*2) --> (4*2) + 4
C4H9OH + 4O2 -> 4CO + 5H2O
Honestly, im not sure, but this wud be my guess.
This equation is C4H8 + 6 O2 -> 4 CO2 + 4 H2O.
2 c4h9oh + 12o2 ---> 8co2 + 10h2o
C4h9oh +6o2 = 4co2 + 5h2o
study
C4H10 + 6.5O2 4CO2 + 5H2O + heat
1-Butene or 2-butene on reaction with concentrated sulphuric acid produce an unstable thick oily liquid sec.butyl sulphonic acid which on dilution with water produce sec.butyl alcohol, the addition follows the Markonikov's rule.
2-butene gives pure Acetaldehyde while 1-butene produces a mixture of Formaldehyde and propionaldehyde.
2-butene is a covalent compound.
reaction of H with 1-butene
C4H8(g) + 6O2(g) ==> 4CO2(g) + 4H2O(g) + Heat.
C4H10 + 6.5O2 4CO2 + 5H2O + heat
1-Butene or 2-butene on reaction with concentrated sulphuric acid produce an unstable thick oily liquid sec.butyl sulphonic acid which on dilution with water produce sec.butyl alcohol, the addition follows the Markonikov's rule.
2-butene gives pure Acetaldehyde while 1-butene produces a mixture of Formaldehyde and propionaldehyde.
2-butene is a covalent compound.
reaction of H with 1-butene
1-butene has four carbon atoms.
2-butene show geomatric isomerism because each double bond carbon atom has two different group
1-butene 2-butene di-n-butyl ether
2-butene is an alkene
2-butanol, CH3CH2CH(OH)CH3 + KMnO4 --------> butanone, CH3CH2COCH3 Butanol: OH | CH3-CH2-C-CH3 + KMnO4 | H Makes: Butanone: O CH3-CH2-C-CH3
2-methyl-2-butene is the major product (85%), while 2-methyl-1-butene the minor (15%) in an E1 reaction.